All categories

2 years ago

Khan Academy btw

Mathematics

1 answer:

Irina-Kira [14]2 years ago

3 0

Answer:

B and D

Step-by-step explanation:

$\frac{2^{5} }{6^{5} } = (\frac{1}{3} )^{5}$

$\frac{2^{5} }{6^{5} } = 2^{5}*6^{-5}$

You might be interested in

Please Help Me!!!!

ra1l [238]

2. WXZ=YXZ
3. Reflexive property of equality
(if they are angles)-
4. WXZ=YXZ ~~Reason- Congruent angles have equal number of degrees
(if they are triangles-more likely judging by the problem)-
4. Triangle WXZ=YXZ ~ Reason- SAS Congruence Postulate

5 0

3 years ago

- 2(x+5) = -2<br> Directions say solve for the equation

erik [133]

Answer:

x = -4

Step-by-step explanation:

Distribute:

-2(x + 5) = -2

-2(x) -2(5) = -2

Multiply:

-2(x) -2(5) = -2

-2x - 10 = -2

Add 10 on both sides:

-2x - 10 = -2

+10 +10

-2x = 8

Divide by -2 on both sides:

-2x = 8

/-2 /-2

x = -4

3 0

3 years ago

Order the numbers least to greatest

Law Incorporation [45]

Answer: C, B, A, D

Step-by-step explanation: i love your pfp

6 0

3 years ago

Lisa wants to build a table and put a border around it. The table and border must have an area of 3,996 square inches. The table

Vinvika [58]

Answer:

The answer is 2,484.

Step-by-step explanation:

First you would have to multiply 42 times 36 then subtract 1,512 from 3,996 you will get 2,484

3 0

3 years ago

The length of a rectangle is three inches more than the width. the area of the rectangle is 180 inches. find the width of the re

ch4aika [34]

We have a rectangle with length L that is 3 inches more than the width W. Then we can write this as:

$L=W+3$

The area of the rectangle is 180 square inches.

We have to find the width W.

As the area is equal to the product of the length and the width, we can write this equation and solve for W as:

$\begin{gathered} A=180 \\ L\cdot W=180 \\ (W+3)\cdot W=180 \\ W^2+3W=180 \\ W^2+3W-180=0 \end{gathered}$

We have a quadratic equation. The roots of this equation will be the mathematical solutions.

We can find the roots using the quadratic formula:

$\begin{gathered} W=\frac{-b\pm\sqrt[]{b^2-4ac}}{2a} \\ W=\frac{-3\pm\sqrt[]{3^2-4\cdot1\cdot(-180)}}{2\cdot1} \\ W=\frac{-3\pm\sqrt[]{9+720}}{2} \\ W=\frac{-3\pm\sqrt[]{729}}{2} \\ W=\frac{-3\pm27}{2} \\ W_1=\frac{-3-27}{2}=-\frac{30}{2}=-15 \\ W_2=\frac{-3+27}{2}=\frac{24}{2}=12 \end{gathered}$

The solutions are W = -15 and W = 12.

The first one is not valid, as W has to be greater than 0.

Then, the solution to our problem is W = 12 in.

Answer: the width is W = 12 inches.

6 0

1 year ago