Answer:
V≈268.08cm³
Step-by-step explanation:
Answer:
-19 y^2 + 18 x y + 13 x^2
Step-by-step explanation:
Simplify the following:
16 x^2 + 15 x y - 19 y^2 - (3 x^2 - 3 x y)
Factor 3 x out of 3 x^2 - 3 x y:
16 x^2 + 15 x y - 19 y^2 - 3 x (x - y)
-3 x (x - y) = 3 x y - 3 x^2:
16 x^2 + 15 x y - 19 y^2 + 3 x y - 3 x^2
Grouping like terms, 16 x^2 + 15 x y - 19 y^2 - 3 x^2 + 3 x y = -19 y^2 + (15 x y + 3 x y) + (16 x^2 - 3 x^2):
-19 y^2 + (15 x y + 3 x y) + (16 x^2 - 3 x^2)
x y 15 + x y 3 = 18 x y:
-19 y^2 + 18 x y + (16 x^2 - 3 x^2)
16 x^2 - 3 x^2 = 13 x^2:
Answer: -19 y^2 + 18 x y + 13 x^2
The answer is a, because the absolute value of x(the actual weight of the product) minus the target weight of 18.25 needs to be greater that the target weight difference of .36 so that it is outside the range. So basically, any number outside of the range will be correct.You can plug in number that you know are in/ out of the acceptable range of numbers for this problem in.
|18.62-18.25|>.36
.37>.36
18.62 is not in range.
Answer:
Converse: if 5=x then x+2=7
Inverse: if x+2 doesnt = 7 then x isnt 5
Contrapositive: if x doesnt equal five then x plus two doesnt equal seven
Step-by-step explanation:
We just did this last week :)
