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2 years ago

7

HELP ASAP! What is the smallest positive number that can be added to 55 so that the resulting number and 45 have 9 as their grea

test common factor?
5

8

9

17

1 answer:

Nikitich [7]2 years ago

8 0

Answer:

It would be 5

Step-by-step explanation:

thank me later! :)

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<img src="https://tex.z-dn.net/?f=3%2F5%20of%205%2F9%5C%5C" id="TexFormula1" title="3/5 of 5/9\\" alt="3/5 of 5/9\\" align="absm

pychu [463]

Answer:

<u>⅓</u>

<h2>Step-by-step explanation:</h2>

$\frac{5}{9} \times \frac{3}{5}$

$= \frac{1}{3} \times \frac{1}{1}$

$= \frac{1}{3}$

<h2>Checking:</h2>

$\frac{1}{3} \div \frac{3}{5}$

$= \frac{1}{3} \times \frac{5}{3}$

$= \frac{5}{9}$

#CarryOnLearning

8 0

3 years ago

Read 2 more answers

Math help, (again) <br><br> These are mainly for corrections

e-lub [12.9K]

The answer would be the last option. :)

4 0

3 years ago

Read 2 more answers

At a popular rock-climbing site in Yosemite National Park, a randomly selected

katrin [286]

Answer:

please be more specific

Step-by-step explanation:

6 0

2 years ago

Write the slope intercept form of the equation of the line through the given point with the given slope

aleksandrvk [35]

Given that,

Point = (-5,3)

Slope, m = -3/5

To find,

The slope intercept form of the equation of the line.

Solution,

The general form of equation is :

y = mx +b

We have, x = -5, y = 3

So,

$3=\dfrac{-3}{5}(-5)+b\\\\3=-3+b\\\\b = 6$

The equation is :

$y=\dfrac{-3}{5}x+6$

Hence, the required equation is $y=\dfrac{-3}{5}x+6$ .

5 0

2 years ago

In △ABC, m∠A=39°, a=11, and b=13. Find c to the nearest tenth.

Talja [164]

For this problem, we are going to use the <em>law of sines</em>, which states:

$\dfrac{\sin{A}}{a} = \dfrac{\sin{B}}{b} = \dfrac{\sin{C}}{c}$

In this case, we have an angle and two sides, and we are trying to look for the third side. First, we have to find the angle which corresponds with the second side, $B$ . Then, we can find the third side. Using the law of sines, we can find:

$\dfrac{\sin{39^{\circ}}}{11} = \dfrac{\sin{B}}{13}$

We can use this to solve for $B$ :

$13 \cdot \dfrac{\sin{39^{\circ}}}{11} = \sin{B}$

$B = \sin^{-1}{\Big(13 \cdot \dfrac{\sin{39^{\circ}}}{11}\Big)} \approx 48.1$

Now, we can find $C$ :

$C = 180^{\circ} - 48.1^{\circ} - 39^{\circ} = 92.9^{\circ}$

Using this, we can find $c$ :

$\dfrac{\sin{39^{\circ}}}{11} = \dfrac{\sin{92.9^{\circ}}}{c}$

$c = \dfrac{11\sin{92.9^{\circ}}}{\sin{39^{\circ}}} \approx \boxed{17.5}$

c is approximately 17.5.

8 0

2 years ago