All categories

2 years ago

CAN SOMEONE PLEASE HELP ME ILL GIVE YOU GOOD RATING

Mathematics

2 answers:

loris [4]2 years ago

8 0

Answer:

Step-by-step explanation:

The sides are the same so it's equilateral and it's acute because it's not more than 180degrees.

Hope this helps plz mark brainliest:D

Nata [24]2 years ago

4 0

Answer:

Your answer is a

Step-by-step explanation:

The little lines on the edge of the triangle mean the sides are equal and the angles are below 90 degrees so they are acute

You might be interested in

Find the value of x.

azamat

Answer:

98 °

Step-by-step explanation:

We know that the sum of the angles in a triangle is 180. We also know that angle DAB is 122°, meaning that angle CAB is 180-122, which is 58°. We also know that angle CBA is 24 degrees. Therefore, angle x is just 180-(58+24), which is 98

3 0

2 years ago

How many times dose 12 go into 41

jonny [76]

Answer:

3.42

Step-by-step explanation:

41/12 is 3.42

3 0

2 years ago

Read 2 more answers

100 POINTS!!

Komok [63]

Answer:

its B,C,and E

Step-by-step explanation:

3 0

2 years ago

Read 2 more answers

At a concession stand, three hot dog(s) and two hamburger(s) cost $8.00; two hot dog(s) and three hamburger(s) cost $8.25. F

qaws [65]

Answer:

$1.5

Step-by-step explanation:

Solve by graphing the system of equations where x = the number of hot dogs and y = the number of hamburgers

> 3x + 2y = 8

> 2x + 3y = 8.25

The solution is (1.5, 1.75)

-- Check attachment for graph

5 0

2 years ago

The projected rate of increase in enrollment at a new branch of the UT-system is estimated by E ′ (t) = 12000(t + 9)−3/2 where E

nexus9112 [7]

Answer:

The projected enrollment is $\lim_{t \to \infty} E(t)=10,000$

Step-by-step explanation:

Consider the provided projected rate.

$E'(t) = 12000(t + 9)^{\frac{-3}{2}}$

Integrate the above function.

$E(t) =\int 12000(t + 9)^{\frac{-3}{2}}dt$

$E(t) =-\frac{24000}{\left(t+9\right)^{\frac{1}{2}}}+c$

The initial enrollment is 2000, that means at t=0 the value of E(t)=2000.

$2000=-\frac{24000}{\left(0+9\right)^{\frac{1}{2}}}+c$

$2000=-\frac{24000}{3}+c$

$2000=-8000+c$

$c=10,000$

Therefore, $E(t) =-\frac{24000}{\left(t+9\right)^{\frac{1}{2}}}+10,000$

Now we need to find $\lim_{t \to \infty} E(t)$

$\lim_{t \to \infty} E(t)=-\frac{24000}{\left(t+9\right)^{\frac{1}{2}}}+10,000$

$\lim_{t \to \infty} E(t)=10,000$

Hence, the projected enrollment is $\lim_{t \to \infty} E(t)=10,000$

8 0

2 years ago