How much force is needed to accelerate a 70kg car at 10m/s^2?

1 answer:

3 0

Momentum (p) is equal to the product of an object's mass (m) and its change in velocity (v).

Change in velocity (v) results in change in momentum (p), which is equal to impulse. Impulse (J) is also equal to an applied force (F) over a period of time (t).

Combining p=mv and J=F t together:

m (v final - v initial) = F t

(2,500 kg) (70 m/s - 30 m/s) = F (10 s)

Solving for F we get:

10,000 N of force

You might be interested in

Heights of 10-year-olds, regardless of gender, closely follow a normal distribution with a mean of 55 inches and a standard devi

Svetllana [295]

Answer:

Step-by-step explanation:

Given that Heights of 10-year-olds, regardless of gender, closely follow a normal distribution with a mean of 55 inches and a standard deviation of 6 inches.

If X is height then X is N(55,6)

Z score would be $\frac{x-55}{6}$

$a) P(X$

b) $P(60$

c) Tallest 10% z = 1.28

X score = $48+1.28(6) = 55.68$ inches

d) $P(X$

i.e. 16.37% cannot go on this ride.

7 0

3 years ago

Read 2 more answers

Sora was given two data sets, one without an outlier and one with an outlier. Data without an outlier: 108, 113, 105, 118, 124,

gladu [14]

The outlier (61) is at the low end of the data set, but doesn't affect the mean by a lot, so ...

The mean is centered among the other numbers in both sets of data.

_____

The mean without the outlier is 114. With the outlier, it is 107.4. The lower quartile is 108, so the mean does get moved outside the "box" of the box-and-whisker plot of the data set without the outlier.

8 0

3 years ago

Read 2 more answers

(4x+2y=84 , 3x + 5y=126) If the system of equations is graphed in a coordinate plane, the coordinates (x, y) of the intersection

pickupchik [31]

x = 12 , y = 18 (12, 18) is the solution, intersection of the two lines.

4 0

3 years ago

A horse corral is situated on a triangular plot of land. Two sides of the plot are 150 feet long and they meet at an angle of 55

Brrunno [24]

Answer : d. 438.5 ft

The diagram for the given statement is attached below.