Bruce has a rope that is 21 feet long he needs to cut the rope into 1/5 long pieces.
The length of the rope = 21 feet
the length of each strip = 
We need to cut the rope 21 feet into strips
To find the number of strips we divide 21 feet by the length of the strip
= 
= 105
105 strips can Bruce cut from his rope.
Answer:
Step-by-step explanation:
Given that :
The enormous sinkhole that appeared in the middle of Guatemalan neighborhood in the year 2010 swallowed a three story building above it and the sinkhole has an estimated depth of about 100 feet
How much material is needed to fill the sinkhole?
Then , the material needed to fill the sinkhole will be dependent on the volume of the sinkhole.
Determine what information is needed to answer the question.
The information that is needed to answer this question are:
the base area of the sinkhole will be required; &
the height should also be known
if the base area is determined then we can proceed to determine how much material is needed to be calculated.
Do you think your estimate is more likely to be too high or too low
No, the estimate is not likely to be too high or too low rather the estimate of the material required will be almost equal to the volume of the sinkhole, but that does not implies that it will be exactly the same since the sinkhole is not uniform and regular in shape.
Answer:
a) distance covered by hare d1 = 8t
b) distance covered by tortoise d2 = 5t + 550
c) ∆d = 550 - 3t
Step-by-step explanation:
Given;
Speed of hare u = 8m/s
Speed of tortoise v = 5 m/s
Initial distance of tortoise d0 = 550 m
a) using the equation of motion;
distance covered = speed × time + initial distance
d = vt + d0
For hare;
d0 = 0
Substituting the values;
d1 = 8t + 0
d1 = 8t
b)using the equation of motion;
distance covered = speed × time + initial distance
d2 = vt + d0
For tortoise;
d0 = 550m
Substituting the values;
d2 = 5t + 550
d2 = 5t + 550 m
c) the number of meters the tortoise is ahead of the hare.
∆d = distance covered by tortoise - distance covered by hare
∆d = d2 - d1
Substituting the values;
∆d = (5t + 550) - 8t
∆d = 550 - 3t
