_______ is 186 more than 207.

24 feet =<br> yds<br> Neeeeeeeeeeeeeed help

torisob [31]

8 yards is your answer

every 3 feet is one yard so just add it up

5 0

3 years ago

Lee is selling spirit wear for a

rewona [7]

Answer:

Lee sold 16 hats

Step-by-step explanation:

16*8=128

12*12=144

128

+ 144

$272

8 0

3 years ago

Read 2 more answers

Joseph jumped off of a cliff into the ocean in Miami while vacationing with some friends. His height as a function of time is gi

Aneli [31]

Answer:

Step-by-step explanation:

I think the missing equation in your question is: h(t) = -16 $t^{2}$ + 16t + 480

Here is my answer:

As we know that the vertex form of a parabola, y=a $(x-h)^{2}$ + k where(h,k) is the vertex

h(t) = -16 $t^{2}$ + 16t + 480

= -16 ( $t^{2} -t)$ + 480

= -16 $(t-\frac{1}{2}) ^{2}$ + 484

So the vertex is ( $\frac{1}{2}$ , 484)

a. It take for Joseph $\frac{1}{2}$ second to reach his maximum height

b. The highest point that Joseph reached is the vertex of the function, it is 484 ft

c. Joseph hit the water after how many seconds?

<=> h(t) = 0

<=> -16 $t^{2}$ + 16t + 480 = 0

<=> t = $\frac{192}{32}$ second = 6 sec

Hope it will find you well

8 0

3 years ago

A doctor is measuring the average height of male students at a large college. The doctor measures the heights, in inches, of a s

denpristay [2]

Answer:

For this case the 95% confidence interval is given (63.5 , 74.4) and we want to conclude about the result. For this case we can say that the true mean of heights for male students would be between 63.5 and 74.4. And the best answer would be:

b. The doctor can be 95% confident that the mean height of male students at the college is between 63.5 inches and 74.4 inches.

Step-by-step explanation:

Notation

$\bar X$ represent the sample mean for the sample

$\mu$ population mean (variable of interest)

s represent the sample standard deviation

n represent the sample size

Solution to the problem

The confidence interval for the mean is given by the following formula:

$\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}$ (1)

In order to calculate the mean and the sample deviation we can use the following formulas:

$\bar X= \sum_{i=1}^n \frac{x_i}{n}$ (2)

$s=\sqrt{\frac{\sum_{i=1}^n (x_i-\bar X)}{n-1}}$ (3)

In order to calculate the critical value $t_{\alpha/2}$ we need to find first the degrees of freedom, given by:

$df=n-1=40-1=39$

For this case the 95% confidence interval is given (63.5 , 74.4) and we want to conclude about the result. For this case we can say that the true mean of heights for male students would be between 63.5 and 74.4. And the best answer would be:

b. The doctor can be 95% confident that the mean height of male students at the college is between 63.5 inches and 74.4 inches.

3 0

4 years ago

What is the volume of a triangular pyramid that has a base area of 8.2 square centimeters and a height of 4

Harman [31]

Answer:

$\boxed {\boxed {\sf V \approx 10.9 \ cm^3}}$