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Oksana_A [137]
3 years ago
7

What is the volume of a triangular pyramid that has a base area of 8.2 square centimeters and a height of 4

Mathematics
1 answer:
Harman [31]3 years ago
5 0

Answer:

\boxed {\boxed {\sf V \approx 10.9 \ cm^3}}

Step-by-step explanation:

The volume of a triangular pyramid can be found using the following formula:

V=\frac{1}{3} A_b\times h

Basically, we have to multiply 1/3, the height, and the base area.

We know that the base area is 8.2 square centimeters and the height is 4 centimeters.

A_b=8.2 \ cm^2 \\h= 4 \ cm

Substitute the values into the formula.

V=\frac{1}{3} (8.2 \ cm^2)\times (4 \ cm)

Multiply 8.2 square centimeters and 4 centimeters.  

  • 8.2 cm² * 4 cm= 32.8 cm³

V=\frac{1}{3} (32.8 \ cm^3)

Multiply 1/3 and 32.8 cubic centimeters.

V= 10.9333333 \ cm^3

Round to the nearest tenth.

The 3 in the hundredth place tells us to leave the 9 in the tenth place.

V \approx 10.9 \ cm^3

The volume of the triangle pyramid is about 10.9 cubic centimeters.

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A bracelet that normally sells for $30.00 is on sale for $25.50. What is the percent discount?
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Answer:

15% off

Step-by-step explanation:

We know we paid $25.50 of the original $30. We can divide these two numbers \frac{25.5}{30}=0.85. This is means we paid 85% of the original price. The discount percentage is the remaining percentage from 85 to 100 which is 15. The pants were 15% off.

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Step-by-step explanation:

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A N S W E R Q U I C K P L E A S E
chubhunter [2.5K]

Answer:

1. A

2. D

3. D

Step-by-step explanation:

The standard form of a parabola is

y=\frac{1}{4p}(x-h)^2+k            ..... (1)

Where, (h,k) is vertex, (h,k+p) is focus and y=k-p is directrix.

1. The directrix of a parabola is y=−8 . The focus of the parabola is (−2,−6) .

k-p=-8                   ...(a)

(h,k+p)=(-2,-6)

k+p=-6            .... (b)

h=-2

On solving (a) and (b),  we get k=-7 and p=1.

Put h=-2, k=-7 and p=1 in equation (1).

y=\frac{1}{4(1)}(x-(-2))^2+(-7)

y=\frac{1}{4}(x+2)^2-7

Therefore option A is correct.

2 The directrix of a parabola is the line y=5 . The focus of the parabola is (2,1) .

k-p=5                   ...(c)

(h,k+p)=(2,1)

k+p=1            .... (d)

h=2

On solving (c) and (d),  we get k=3 and p=-2.

Put h=2, k=3 and p=-2 in equation (1).

y=\frac{1}{4(-2)}(x-(2))^2+(3)

y=-\frac{1}{8}(x-2)^2+3

Therefore option D is correct.

3. The focus of a parabola is (0,−2) . The directrix of the parabola is the line y=−3 .

k-p=-3                   ...(e)

(h,k+p)=(0,-2)

k+p=-2            .... (f)

h=0

On solving (e) and (f),  we get k=-2.5 and p=0.5.

Put h=0, k=-2.5 and p=0.5 in equation (1).

y=\frac{1}{4(0.5)}(x-(0))^2+(-2.5)

y=\frac{1}{2}(x)^2-2.5

y=\frac{1}{2}(x)^2-\frac{5}{2}

Therefore option D is correct.

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liraira [26]

Answer:

Step-by-step explanation:

the lines weren't really clear so sorry if its a bit messy

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