Answer:
3pf² - 21p²f + 6pf - 42p²
= 3pf² + 6pf - 21p²f - 42p²
= 3pf(f +2) - 21p²(f + 2)
= (3pf - 21p²)(f +0 2)
Answer: (3pf - 21p²)(f + 2)
Step-by-step explanation:
Answer:
B
Step-by-step explanation:
i had that same question to answer and got it right
♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️
13 ) Go...
Factor x
These are the zeroes.
♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️
14 ) Go...
These are the zeroes.
♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️
Answer:
hello :
note : 1²+2²+3²+........+n² = n(n+1)(n+2)/6
Step-by-step explanation:
let : S = 1²+2²+3²+......+25²
A = 16²+17²+18²+...+25²
B = 1²+2²+3²+......+15²
S = (1²+2²+3²+....+15²) + (16²+17²+18²+...+25²)
calculate : S for : n = 25
S = 25(26)(27)/6 = 2925
calculate : B for : n = 15
B = 15(16)(17)/6 = 680
so : S = B + A
A = S - B = 2925 - 680 = 2245
Answer:
Step-by-step explanation:
F=9/5C+32 should be F = (9/5)C + 32
We are given 111 degrees F and want the same temperature in degrees Celcius.
In F = (9/5)C + 32 multiply all three terms by 5:
5F = 9C + 160, which can be solved for C:
5F - 160 = 9C
Let F = 111. Then 555 - 160 = 9C, or
395 = 9C
Dividing both sides by 9, we get C = 395/9 = 43 8/9 degrees C
