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3 years ago

9

PLEASE HELP I NEED THIS FAST

1 answer:

aleksley [76]3 years ago

4 0

Answer:

Knowing others is intelligence; knowing yourself is true wisdom. mastering others is strength; mastering yourself is true power. if you realize that you have enough, you are truly rich, "And the cause of not following your heart, is in spending the rest of your life wishing you had."

Explanation:

I need points so SORRY!

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a piece of note paper has side length of 12.5 centimetres what is the area of the piece of note paper

muminat

If the note paper is a square, the answer would be 156.25cm^2

6 0

4 years ago

Write the following as an inequality

Ipatiy [6.2K]

Answer:

3 ≤ w ≤ 4

Step-by-step explanation:

the statements are 3 ≤ w and 4 ≥ w ( or w ≤ 4 )

These can be combined into the single inequality

3 ≤ w ≤ 4

4 0

3 years ago

Tony and some friends went to the movies. They bought 4 drinks and 2 tubs of popcorn and spent a total of $32.50 on the food. Ea

Travka [436]

1 tub of popcorn = t
1 drink = t - 3.5

4(t - 3.5) + 2t = $32.50
4t - 14 + 2t = 32.5
6t = 32.5 + 14
6t = 46.5
t = 46.5 / 6
t = $7.75

7 0

3 years ago

Evaluate the expression when a = 30 and b=6.

Lena [83]

Answer:

a+b2

a+4b

Now,

30+6×2

30-4×6

30+12

30-24

42

6

7 0

4 years ago

Miss Berk has 8 pairs of pajama pants and 3 pairs of slippers. Three pairs of the pajama pants are Harry Potter themed and one p

shusha [124]

The probability that both items will be Harry Potter themed is 1/8.

<u>Step-by-step explanation:</u>

Total Number of pajama pants n(P) =8

Total number of slippers n(S)= 3

Number of Harry Potter themed Pajama pants n(H.P)=3

Number of Harry Potter themed slippers n(H.S)=1

We have to determine the probability of selecting pants and slippers that are both Harry Potter themed.

If two events A and B are independent, then the probability of A and B is given by

P(A and B)=P(A)*P(B)

Here the events selecting Harry potter themed pants and selecting harry Potter themed slippers are independent.

$P(Harry\ Potter\ pants)=\frac{n(H.P)}{n(P)}$

$=\frac{3}{8}$

$P(Harry\ Potter\ slippers)=\frac{n(H.S)}{n(S)} \\ =1/3$

$P(Harry\ Potter\ pants\ and\ Harry\ Potter\ slippers)=P(Harry Potter pants)\times P(Harry potter slippers)$

$=\frac{3}{8}\times \frac{1}{3} =\frac{1}{8}$

Hence probability of selecting Harry potter themed pants and Harry potter themed slippers is 1/8

3 0

4 years ago

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