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Harrizon [31]
3 years ago
9

What is the center of a circle whose equation is x

Mathematics
1 answer:
jeyben [28]3 years ago
3 0

Answer:

(6, 1)

Step-by-step explanation:

{x}^{2}  +  {y}^{2}  - 12x - 2y + 12 = 0 \\ equating \: it \: with \\  {x}^{2}  +  {y}^{2}   + 2gx  + 2fy + c= 0 \\we \: find \\ 2g =  - 12 \implies \: g =  - 6 \\ 2f =  - 2 \implies \: f =  - 1 \\ center \: of \: circle = ( - g \:  \:  - f) \\ center \: of \: circle = (6 \:  \: 1)

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