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posledela
2 years ago
6

What information do you need to know to calculate last year’s winning speed? Remember, the distance traveled (length of the cour

se) is equal to the rate (boat’s speed) times the time.
Mathematics
1 answer:
Andrews [41]2 years ago
8 0

Answer:

1. Total distance

2. Shortest time taken

Step-by-step explanation:

Since it is a competition the distance will be the same for all participants.

therefore the information need is

1.  The total distance of the competition

2. The time taken by each participant to complete the race

The winning speed is the speed is given as the distance covered in the shortest possible time.

hence the winning speed is expressed as

winning speed= distance/short time taken

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Write (5.64) x 10-7 as a decimal.
Cloud [144]

Answer:

16.92

Step-by-step explanation:

5.64 x 3 = 16.92

<em>Hope that helps!</em>

3 0
3 years ago
Freddy wants an average grade of 93 from his four algebra exams. The scores for his first three exams are 94, 89, and 96. What g
White raven [17]
He would need a 93% on his fourth exam.

94+89+96+93= 372, 372 divided by 4= 93
8 0
2 years ago
Simplify 3(x + 2) + 4(x - 5)<br><br> 7x - 3<br> 7x + 26<br> 7x - 14
Molodets [167]

Answer:

Step-by-step explanation:

2(13x – 7). 11.

7 0
2 years ago
Read 2 more answers
OH NO i forgot what 2 + 2 is helppp (lol)
trasher [3.6K]

Answer:

4

Step-by-step explanation:

7 0
2 years ago
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Please solve the question below 88
RideAnS [48]

Answer:

7361.56 yards

Step-by-step explanation:

Height of the tower = 906 yards

Mauricio's height = 2 yards

Angle of elevation = 7^{o}

Let the distance between Mauricio and the base of the tower be represented by x.

The difference between the height of tower and Mauricio's height = 906 - 2

                                               = 904 yards

So that applying the appropriate trigonometric function, we have;

Tan θ = \frac{opposite}{adjacent}

Tan 7^{o}  = \frac{904}{x}

0.1228 = \frac{904}{x}

x = \frac{904}{0.1228}

  = 7361.5635

x = 7361.56 yards

The distance between Mauricio and the base of the tower is 7361.56 yards.

3 0
3 years ago
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