Can someone help me please I need this grade
2 answers:
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See the attached figure.
m ∠KAJ = 170° & m ∠LAM = 80°
We should know that :
m ∠KAJ + m ∠LAM + m ∠KAL + m ∠MAJ = 360°
∴ m ∠KAL + m ∠MAJ = 360° - (m ∠KAJ + m ∠LAM)
∴ m ∠KAL + m ∠MAJ = 360° - (170°+80°) = 360° - 250° = 110°
But : m ∠KAL = m ∠MAJ ⇒⇒⇒ <u>Opposite angles.</u>
∴ m ∠MAJ + m ∠MAJ = 110°
∴ 2 * m ∠MAJ = 110°
∴ m ∠MAJ = 110° ÷ 2 = 55°
<u>So, the answer is : m ∠MAJ = 55°</u>
Answer:
The price of 1 adult ticket is $ 11 and price of 1 child ticket is $13
Step-by-step explanation:
Let x be the cost of 1 adult ticket
Let y be the cost of 1 child ticket
Cost of 8 adult tickets = 8x
Cost of 9 child tickets = 9y
We are given that A local kids play sold 8 adult tickets and 9 child tickets for a total of $205
So, 8x+9y=205 ----- 1
Cost of 4 adult tickets = 4x
Cost of 3 child tickets = 3y
We are given that 4 adult tickets and 3 child tickets for a total of $83.
4x+3y=83 ----2
Plot 1 and 2 on graph
8x+9y=205 -- Red line
4x+3y=83 -- Blue line
Intersection point provides the solution
So, Intersection point =(11,13)
So, The price of 1 adult ticket is $ 11 and price of 1 child ticket is $13
