X² - 7x + 10 = 0
Let's factor out the equation first.
x² - 7x + 10
x -2
x -5
This factoring of (x-2)(x-5) fit the equation.
(x-2)(x-5) = 0
One of the factors must equal 0 as to equal zero.
Either x - 2 = 0 or x - 5 = 0
x - 2 = 0
x = 2
x - 5 = 0
x = 5
The two answers are x = 2 or x = 5. Hope this helps!
Answer:
Step-by-step explanation:
calculates the unit price as $13.56 per pair for the expense report.The correct unit price is $nothing per pair. Roger could feed 5 walruses with 4 kilograms of fish. how many walruses could he ... Error Analysis A contractor purchases 5 dozen pairs of padded work gloves for $67.80 incorrectly
Answer:
length = 6 cm
width = 1 cm
Step-by-step explanation:
l = length
w = width
l = 4 + 2w
2(4 + 2w) + 2w = 14
8 + 4w + 2w = 14
8 + 6w = 14
6w = 6
w = 1
find length:
l = 4 + 2(1)
l = 6
Answer: The common number is 26.
Step-by-step explanation:
We know that the n-th term of a sequence is:
aₙ = 3*n^2 - 1
And the n-th term of another sequence is:
bₙ = 30 - n^2
Remember that in a sequence n is always an integer number.
We want to find a number that belongs to both sequences, then we want to find a pair of integers x and n, such that:
aₙ = bₓ
This is:
3*n^2 - 1 = 30 - x^2
Let's isolate one of the variables, i will isolate n.
3*n^2 = 30 - x^2 + 1 = 31 - x^2
n^2 = (31 - x^2)/3
n = √( (31 - x^2)/3)
Now we can try with different integer values of x, and see if n is also an integer.
if x = 1
n = √( (31 - 1^2)/3) = √10
We know that √10 is not an integer, so we need to try with another value of x.
if x = 2:
n = √( (31 - x^2)/3) = √(27/3) = √9 = 3
Then if we have x= 2, n is also an integer, n = 3.
Then we have:
a₃ = b₂
The common number between both sequences is:
a₃ = 3*(3)^2 - 1 = 26
b₂ = 30 - 2^2 = 26
