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Gemiola [76]
3 years ago
13

Dale is spreading grass seed over the putting green on a golf course. The circular green is centered about the cup with a radius

of 30 feet. If each bag of grass seed covers 315 ft^2, how many bag(s) of grass seed does Dale need? QUESTION FROM MATH NATION!!!
Mathematics
2 answers:
xenn [34]3 years ago
6 0

Answer:

9 bags

Step-by-step explanation:

Total area = 3.14 × 30²

= 2,826

No. of bags:

2,826/315

= 8.9714285714

To cover the area, he needs 9 bags

kozerog [31]3 years ago
5 0

Answer:

9 bags

Step-by-step explanation:

We need to find the area of the putting green with a radius of 30 ft

A = pi r^2

A = 3.14 (30)^2

A =2826 ft^2

Each bag will cover 315 ft^2

Divide the area by 315 ft^2 to determine the number of bags

2826/315 =8.971428571 bags

Rounding up to the nearest bag

9 bags

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A 15 kilogram object is suspended from the end of a vertically hanging spring stretches the spring 1/3 meters. At time t = 0, th
Yuri [45]

Answer:

15\frac{d^{2}y(t)}{dt^{2} }  - 441.45y(t) = ± 170 cos(5t)

y(0)=0, y'(0)=0

Step-by-step explanation:

See the attached image

This problem involves Newton's 2nd Law which is: ∑F = ma, we have that the acting forces on the mass-spring system are: F_{r} (t) that correspond to the force of resistance on the mass by the action of the spring and F(t) that is an external force with unknown direction (that does not specify in the enounce).

For determinate F_{r} (t) we can use Hooke's Law given by the formula F_{r} (t) = k y(t) where k correspond to the elastic constant of the spring and y(t) correspond to  the relative displacement of the mass-spring system with respect of his rest state.

We know from the problem that an 15 Kg mass stretches the spring 1/3 m so we apply Hooke's law and obtain that...

k = \frac{F_{r}}{y} = \frac{mg}{y} = \frac{15 Kg (9.81 \frac{m}{s^{2} } )}{\frac{1}{3} m}  = 441.45 \frac{N}{m}

Now we apply Newton's 2nd Law and obtaint that...

F_{r} (t) ± F(t) = ma(t)

F_{r} (t) = ky(t) = 441.45y(t)

F(t) = 170 cos(5t)

m = 15 kg

a(t) = \frac{d^{2}y(t)}{dt^{2} }

Finally... 15\frac{d^{2}y(t)}{dt^{2} }  - 441.45y(t) = ± 170 cos(5t)

We know from the problem that there's not initial displacement and initial velocity, so... y(0)=0 and y'(0)=0

Finally the Initial Value Problem that models the situation describe by the problem is

\left \{ 15\frac{d^{2}y(t)}{dt^{2} }  - 441.45y(t) = \frac{+}{} 170 cos(5t) \atop {y(0)=0, y'(0)=0\right.

6 0
3 years ago
Simplify negative 2 and 1 over 6 – negative 7 and 1 over 3. negative 5 and 1 over 6 negative 9 and 3 over 6 9 and 3 over 6 5 and
luda_lava [24]

Answer:

5 and 1 over 6

Step-by-step explanation:

<u>Simplifying the given:</u>

  • Negative 2 and 1 over 6 – negative 7 and 1 over 3 ⇒ <em>translated as</em>:
  • - 2 1/6 - (-7 1/3) =         ⇒ <em>cancelling negatives and changing mixed fractions to improper fractions</em>
  • - 13/6 + 22/3 =            ⇒ <em>bringing to same denominator</em>
  • - 13/6 + 44/6 =            ⇒ calculating the numerator
  • 31/6 =                          ⇒ making mixed fraction
  • 5 1/6                            ⇒ answer

<u>Correct choice is the last one: </u>5 and 1 over 6

4 0
4 years ago
Read 2 more answers
P(x)=2x^4-x^3+2x^2-6. What is the remainder when P(x) is divided by (x-2)?
aleksandr82 [10.1K]

Answer: 26

Step-by-step explanation: From the remainder theorem ,

If P (x) = 2x⁴ ⁻ x³ + 2x² ⁻ 6. is divided by ( x - 2 ).

It means that if P(x) is divided by (x - 2 ) and leaves a Remainder, it implies that x - 2 is not a factor of P(x) , but if it leaves no remainder, it means x-2 is a factor of P(x).

Therefore , to find the remainder, find the zero of x - 2, and substitutes for the value in P(x)  to know the remainder

x - 2 = 0

x = 2

Now put this in P(x)

P(x) = 2(2)⁴ - (2)³ + 2(2)² - 6

= 2(16) -8 + 2(4) -6

= 32 -8 +8 -6

=26

Therefore the remainder when P(x) is divided by x -2

=26

Note: Since the division of P(x) by x - 2 leaves a remainder, it means that

x - 2 ≠ a factor of P(x)

4 0
3 years ago
Find the missing side of the triangle
lara [203]

Answer:

3 (equalateral)

Step-by-step explanation:

7 0
3 years ago
What is the length of a ramp whose rise is 10 feet and slope is 5/12
polet [3.4K]

Answer:

120 feet

Step-by-step explanation:

Length/height =second number in ratio (here's it is 12)

L/10=12

Therefore length will be 120

3 0
4 years ago
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