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eduard
2 years ago
15

Ernesto used 2/3 of a cup of frosting to decorate some cupcakes. He divided all the frosting equally among 4 cupcakes. How much

frosting did Ernesto use on each cupcake?
Mathematics
1 answer:
Lelu [443]2 years ago
8 0

Answer:

1/6

Step-by-step explanation:

We are told that:

Ernesto used 2/3 of a cup of frosting to decorate some cupcakes.

He divided all the frosting equally among 4 cupcakes.

The amount of frosting Ernesto used on each cupcake is calculated as:

2/3 cup ÷ 4 cupcakes

= 2/3 × 1/4

= 2/12

= 1/6 of 2/3cup of frosting was used on each cupcake

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3 years ago
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Maristella is constructing an isosceles triangle to use as a model in her Algebra class. The perimeter of her triangle is 24 cm.
Vlada [557]

Isolating s, the equation written in terms of s is:

s = 12 - 0.5b

-------------------------

  • The equation for the length of the third side, as stated in the problem,("Maristella uses the equation b = 24 – 2s to find b, the length of the triangle's third side") is:

b = 24 - 2s

  • To solve for the lengths of the congruent sides, we isolate s, thus:

b = 24 - 2s

2s = 24 - b

Inverse of multiplication is division, thus:

s = \frac{24 - b}{2}

Separating into two fractions:

s = \frac{24}{2} - \frac{b}{2}

Solving each fraction:

s = 12 - 0.5b

A similar problem is given at brainly.com/question/5123313

3 0
3 years ago
What is Limit of StartFraction StartRoot x + 1 EndRoot minus 2 Over x minus 3 EndFraction as x approaches 3?
scoray [572]

Answer:

<u />\displaystyle \lim_{x \to 3} \frac{\sqrt{x + 1} - 2}{x - 3} = \boxed{ \frac{1}{4} }

General Formulas and Concepts:

<u>Calculus</u>

Limits

Limit Rule [Variable Direct Substitution]:
\displaystyle \lim_{x \to c} x = c

Special Limit Rule [L’Hopital’s Rule]:
\displaystyle \lim_{x \to c} \frac{f(x)}{g(x)} = \lim_{x \to c} \frac{f'(x)}{g'(x)}

Differentiation

  • Derivatives
  • Derivative Notation

Derivative Property [Addition/Subtraction]:
\displaystyle \frac{d}{dx}[f(x) + g(x)] = \frac{d}{dx}[f(x)] + \frac{d}{dx}[g(x)]
Derivative Rule [Basic Power Rule]:

  1. f(x) = cxⁿ
  2. f’(x) = c·nxⁿ⁻¹

Derivative Rule [Chain Rule]:
\displaystyle \frac{d}{dx}[f(g(x))] =f'(g(x)) \cdot g'(x)

Step-by-step explanation:

<u>Step 1: Define</u>

<em>Identify given limit</em>.

\displaystyle \lim_{x \to 3} \frac{\sqrt{x + 1} - 2}{x - 3}

<u>Step 2: Find Limit</u>

Let's start out by <em>directly</em> evaluating the limit:

  1. [Limit] Apply Limit Rule [Variable Direct Substitution]:
    \displaystyle \lim_{x \to 3} \frac{\sqrt{x + 1} - 2}{x - 3} = \frac{\sqrt{3 + 1} - 2}{3 - 3}
  2. Evaluate:
    \displaystyle \begin{aligned}\lim_{x \to 3} \frac{\sqrt{x + 1} - 2}{x - 3} & = \frac{\sqrt{3 + 1} - 2}{3 - 3} \\& = \frac{0}{0} \leftarrow \\\end{aligned}

When we do evaluate the limit directly, we end up with an indeterminant form. We can now use L' Hopital's Rule to simply the limit:

  1. [Limit] Apply Limit Rule [L' Hopital's Rule]:
    \displaystyle \begin{aligned}\lim_{x \to 3} \frac{\sqrt{x + 1} - 2}{x - 3} & = \lim_{x \to 3} \frac{(\sqrt{x + 1} - 2)'}{(x - 3)'} \\\end{aligned}
  2. [Limit] Differentiate [Derivative Rules and Properties]:
    \displaystyle \begin{aligned}\lim_{x \to 3} \frac{\sqrt{x + 1} - 2}{x - 3} & = \lim_{x \to 3} \frac{(\sqrt{x + 1} - 2)'}{(x - 3)'} \\& = \lim_{x \to 3} \frac{1}{2\sqrt{x + 1}} \leftarrow \\\end{aligned}
  3. [Limit] Apply Limit Rule [Variable Direct Substitution]:
    \displaystyle \begin{aligned}\lim_{x \to 3} \frac{\sqrt{x + 1} - 2}{x - 3} & = \lim_{x \to 3} \frac{(\sqrt{x + 1} - 2)'}{(x - 3)'} \\& = \lim_{x \to 3} \frac{1}{2\sqrt{x + 1}} \\& = \frac{1}{2\sqrt{3 + 1}} \leftarrow \\\end{aligned}
  4. Evaluate:
    \displaystyle \begin{aligned}\lim_{x \to 3} \frac{\sqrt{x + 1} - 2}{x - 3} & = \lim_{x \to 3} \frac{(\sqrt{x + 1} - 2)'}{(x - 3)'} \\& = \lim_{x \to 3} \frac{1}{2\sqrt{x + 1}} \\& = \frac{1}{2\sqrt{3 + 1}} \\& = \boxed{ \frac{1}{4} } \\\end{aligned}

∴ we have <em>evaluated</em> the given limit.

___

Learn more about limits: brainly.com/question/27807253

Learn more about Calculus: brainly.com/question/27805589

___

Topic: AP Calculus AB/BC (Calculus I/I + II)

Unit: Limits

3 0
2 years ago
Please help will give brainliest
Gelneren [198K]

Answer:

B

Step-by-step explanation:

It is B because to find the volume you multiply all three values together, which gets you 68.448. I multiplied 9.2x3.1, which got me 28.52, and then I multiplied 28.52 by 2.4 which got me 68.448.

6 0
3 years ago
Find the value of nif 2n=1​
hram777 [196]

Answer:

n=0.5

Step-by-step explanation:

2 times 0.5 = 1

5 0
3 years ago
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