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Svetlanka [38]
3 years ago
5

What are two other names for ray CD?

Mathematics
1 answer:
Masja [62]3 years ago
6 0
<span>Naming of rays Rays are commonly named in two ways: By two points. In the figure at the top of the page, the ray would be called AB because starts at point A and passes through B on it's way to infinity. Recall that points are usually labelled with single upper-case (capital) letters. There is a symbol for this which looks like this: AB This is read as "ray AB". The arrow over the two letters indicates it is a ray, and the arrow direction indicates that A is the point where the ray starts. By a single letter. (I have not seen this done.) The ray above would be called simply "q". By convention, this is usually a single lower case (small) letter. This is normally used when the ray does not pass through another labeled point.</span>
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6m-2 = m+13 how do i solve it
kakasveta [241]
First move the terms to get
6m-m=13+2
Then collect the like terms and calculate the sum, 5m=15
Divide both sides by 5
And you get m=3
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3 years ago
If a cross section was cut that was parallel to the base of a triangular prism below a shape with that cross section be ?
velikii [3]
The answer is A) square
6 0
2 years ago
Read 2 more answers
For a boat to float in a tidal bay, the water must be at least 2.5 meters deep. The depth of water around the boat, ????(????),
Effectus [21]

Answer:

a. Period, T = 12.57 hours. b. Latest time = 294.16 hours, 6 a.m 12 days later

Step-by-step explanation:

For a boat to float in a tidal bay, the water must be at least 2.5 meters deep. The depth of water around the boat, d(t), in meters, where t is measured in hours since midnight, is d(t) = 5 + 4.6sin(0.5t). (a) What is the period of the tides in hours? (b) If the boat leaves the bay at midday, what is the latest time it can return before the water becomes too shallow?

a. The period, T of the tides is gotten from ω = 2π/T, where ω is the angular frequency of the wave and T its period. Comparing the sine part of equation of the tides with the general equqtion of a sine wave, Asinωt, thus Asinωt = 4.6sin(0.5t),

so ω = 0.5 rad/s.

Equating this to 2π/T implies

0.5 = 2π/T

therefore, T = 2π/0.5 = 12.566 hours ≈ 12.57 hours

b. The tide becomes too low if it is less than 2.5 m i.e d(t) < 2.5 m. So, equating d(t) as 2.5 in the tidal equation, we have d(t) = 5 + 4.6sin(0.5t).

2.5< 5+ 4.6sin(0.5t)

2.5-5 < 4.6sin(0.5t)

-2.5 < 4.6sin(0.5t)

-2.5/4.6 < sin(0.5t)

-0.543 < sin(0.5t)

sin⁻¹(-0.543)<0.5t

-32.92<0.5t. Since we cannot have negative time, we add 180 to -32.92 to give 147.08

147.08<0.5t

t>147.08/0.5=294.16 hours

So, if t is greater than 294.16 hours, the water will be shallow. That is, below 2.5 m. which is 12 days 6hours 8 min 38 s which is 6 a.m 12 days later

3 0
3 years ago
Find the median of the data.<br><br> 5, 8, 4, 6, 8
Ksenya-84 [330]

Answer:

Step-by-step explanation:

4

8 0
2 years ago
In ΔOPQ, the measure of ∠Q=90°, the measure of ∠P=54°, and OP = 68 feet. Find the length of PQ to the nearest foot.
Morgarella [4.7K]

Answer:

PQ= 40 feet (nearest foot)

Step-by-step explanation:

Please see attached picture for full solution.

sin angle= opp/hyp

cos angle= adj/hyp

tan angle= opp/adj

6 0
3 years ago
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