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andriy [413]
4 years ago
13

LaTeX: \frac18 \cdot 7 = \text{_______}

Mathematics
2 answers:
Mashutka [201]4 years ago
7 0
Question 6 is 1.

Question 7 is 24/8 or 3.

Question 8 is 7/8.

Apologies if I'm wrong.
ivolga24 [154]4 years ago
5 0
It’s gonna be 7/8 sorry if I’m wrong!
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Which statement is true about polynomial 5s^6t^2 + 6st^9 - 8s^6t^2 - 6t^7 after it has been fully simplified?
Marina86 [1]

Answer:  3t²(2st⁷ - s⁶ - 2t⁵)

<u>Step-by-step explanation:</u>

5s⁶t² + 6st⁹ - 8s⁶t² - 6t⁷     <em>5s⁶t² and - 8s⁶t² are like terms which = -3s⁶t² when combined</em>

=          6st⁹ - 3s⁶t² - 6t⁷      <em>next, factor out the GCF of 3t²</em>

=      3t²(2st⁷ - s⁶ - 2t⁵)

5 0
3 years ago
Read 2 more answers
The empty gas tank of a motor boat is to be filled. The tank is shaped like a rectangular prism with length 20 cm, width
Minchanka [31]

Answer:

t

Step-by-step explanation:

t

8 0
3 years ago
Simplify. 32 + 16 + 8 A) 4 + 6 2 B) 6 + 4 2 C) 10 + 2 D) 10 2
Ann [662]

Answer:

its 56 if you simplify 32 + 16 + 8

6 0
4 years ago
Hi guys, can anyone help me with this triple integral? Many thanks:)
Crank

Another triple integral.  We're integrating over the interior of the sphere

x^2+y^2+z^2=2^2

Let's do the outer integral over z.   z stays within the sphere so it goes from -2 to 2.

For the middle integral we have

y^2=4-x^2-z^2

x is the inner integral so at this point we conservatively say its zero.  That means y goes from -\sqrt{4-z^2} and +\sqrt{4-z^2}

Similarly the inner integral x goes between \pm-\sqrt{4-y^2-z^2}

So we rewrite the integral

\displaystyle \int_{-2}^{2} \int_{-\sqrt{4-z^2}}^{\sqrt{4-z^2}} \int_{-\sqrt{4-y^2-z^2}}^{\sqrt{4-y^2-z^2}} (x^2+xy+y^2)dx \; dy \; dz

Let's work on the inner one,

\displaystyle\int_{-\sqrt{4-y^2-z^2}}^{\sqrt{4-y^2-z^2}} (x^2+xy+y^2)dz

There's no z in the integrand, so we treat it as a constant.

=(x^2+xy+y^2)z \bigg|_{z=-\sqrt{4-y^2-z^2}}^{z=\sqrt{4-y^2-z^2}}

So the middle integral is

\displaystyle\int_{-\sqrt{4-z^2}}^{\sqrt{4-z^2}}2(x^2+xy+y^2)\sqrt{4-y^2-z^2} \ dy  

I gotta go so I'll stop here, sorry.

7 0
3 years ago
Read 2 more answers
Suppose you know the area of the yard is 7,500 square feet. How can you find the value of a?
tia_tia [17]

Answer:

a = 50

Step-by-step explanation:

From the introduction, you know that the area is 3a^2

You also know that it is 7500 square feet. \

So the two must be equal

3a^2 = 7500                    Divide by 3

a^2 = 7500/3

a^2 = 2500

The square root of 2500 is 50

sqrt(a^2) = sqrt(2500)

a = 50

8 0
3 years ago
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