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NeTakaya
3 years ago
6

4-2[-3(-2-4) 2(-5-1)] what is the answer

Mathematics
1 answer:
zloy xaker [14]3 years ago
6 0
4 - 2[-3(-2 - 4) + 2(-5 - 1)] = 4 - 2[-3(-6) + 2(-6)] = 4 - 2[18 - 12] = 4 - 2(6) = 4 - 12 = -8
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Henry and Blake are both runners. In 2 hours, Henry runs 14 miles. In 5 hours, Henry runs 35 miles. The graph below represents t
Tasya [4]
Henry runs at a rate of seven miles an hour. I think you meant the second sentence to be 'Blake', because there is not attatched graph. They are both running at the same speed in this case.

I got this because 14 (miles ran by Henry) / 2 (hours ran) you get 7. This same equation is applied to (Blake?) 35 (miles ran by [Blake?]) / 5 (hours ran) also equals seven.

If you meant the second statement to be Blake, they are both running at the same speed, and x=7.

If you didn't, then there is not enough information to determine Blake's speed.

If you found this especially helpful, I'd appreciate if you'd vote me Brainliest for your answer. I want to be able to assist more users one-on-one, as well as to move up in rank! :)
3 0
3 years ago
Translate and simply: subtract 18 from -11
navik [9.2K]
Answer: -29

Subtract 18 FROM -11.
That means that 18 would go after -11.

-11 - 18 = -29
4 0
3 years ago
I need help with this question
Amiraneli [1.4K]

Answer:

what is the question be more specific

7 0
3 years ago
Read 2 more answers
1. In order to get more female customers, a new clothing store offers free gourmet coffee and pastry to its customers. The avera
ioda

Answer:

No, the manager is not correct based on the 95% confidence interval.

Step-by-step explanation:

We are given that the average daily revenue over the past five-week period has been $1,080 with a standard deviation of $260, i.e.; X bar = $1080 and s = $260 and sample size, n = 35 .

The Pivotal quantity for 95% confidence interval is given by;

                \frac{Xbar - \mu}{\frac{s}{\sqrt{n} } } ~ t_n_-_1

where, X bar = sample mean = $1080

                s  = sample standard deviation = $260

                 n = sample size = 35 {five-week}

So, 95% confidence interval for average daily revenue, \mu is given by;

P(-2.032 < t_3_4 < 2.032) = 0.95

P(-2.032 < \frac{Xbar - \mu}{\frac{s}{\sqrt{n} } } < 2.032) = 0.95

P(-2.032 * {\frac{s}{\sqrt{n} } < {Xbar - \mu} < 2.032 * {\frac{s}{\sqrt{n} } ) = 0.95

P(X bar - 2.032 * {\frac{s}{\sqrt{n} } < \mu < X bar + 2.032 * {\frac{s}{\sqrt{n} } ) = 0.95

95% confidence interval for \mu = [ X bar - 2.032 * {\frac{s}{\sqrt{n} } , X bar + 2.032 * {\frac{s}{\sqrt{n} } ]

                                            = [ 1080 - 2.032 * {\frac{260}{\sqrt{35} } , 1080 + 2.032 * {\frac{260}{\sqrt{35} } ]

                                             = [ 990.70 , 1169.30 ]

<em>No, the manager is not correct based on the fact that the coffee and pastry strategy would lead to an average daily revenue of $1,200 because the calculate 95% confidence interval does not include value of $1200.</em>

Therefore, the store manager believe is not correct.

8 0
3 years ago
Which of the following triangle congruence theorems would be used in this proof?
HACTEHA [7]

The answer is SSS congruency.

AB=CD (given)

BC=DA (given)

AC=AC (common side)

∴ΔADC≅ΔABC

Please mark brainliest if this helps!

5 0
3 years ago
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