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oksian1 [2.3K]
3 years ago
11

Find the value of xthe options are:897107117PLEASE HURRYYY​

Mathematics
1 answer:
antiseptic1488 [7]3 years ago
3 0

Answer:

107 degrees

Step-by-step explanation:

All polygon degrees add up to 360

we know that this polygon has a angle of 90 and 56

subtract 90 and 56 from 360 to get 214

Then divide by 2 because there are 2 x angles

to get 107 degrees

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27.36 divided by 3.14 use compatible numbers to estimate the quotient
stiks02 [169]

Answer:

Step-by-step explanation:

you can round the numbers

27/3= 9

27.36 rounds down to 27 and 3.14 rounds to 3

6 0
3 years ago
Read 2 more answers
Find the volume. SHOW WORK
Anettt [7]

Answer:

827.39

Step-by-step explanation:

Volume = L X W X H

So 6.2 X 8.5 X 15.7

6.2 X 8.5 = 52.7

52.7 X 15.7 = 827.39

So the volume is <u>827.39</u>

3 0
3 years ago
Read 2 more answers
A soccer ball is kicked toward the goal. The height of the ball is modeled by the function h(t) = - 16t^2 + 48t where t equals t
andriy [413]

Answer:

x = 3/2

The axis of symmetry is located at the vertex,

which is the also the highest point in this problem...

the x component of the vertex can be calculated as -b/2a = -48/-32 = 24/16 = 6/4 = 3/2

x = 3/2

Step-by-step explanation:

8 0
3 years ago
6. If the net investment function is given by
Pachacha [2.7K]

The capital formation of the investment function over a given period is the

accumulated  capital for the period.

  • (a) The capital formation from the end of the second year to the end of the fifth year is approximately <u>298.87</u>.

  • (b) The number of years before the capital stock exceeds $100,000 is approximately <u>46.15 years</u>.

Reasons:

(a) The given investment function is presented as follows;

I(t) = 100 \cdot e^{0.1 \cdot t}

(a) The capital formation is given as follows;

\displaystyle Capital = \int\limits {100 \cdot e^{0.1 \cdot t}} \, dt =1000 \cdot  e^{0.1 \cdot t}} + C

From the end of the second year to the end of the fifth year, we have;

The end of the second year can be taken as the beginning of the third year.

Therefore,  for the three years; Year 3, year 4, and year 5, we have;

\displaystyle Capital = \int\limits^5_3 {100 \cdot e^{0.1 \cdot t}} \, dt \approx 298.87

The capital formation from the end of the second year to the end of the fifth year, C ≈ 298.87

(b) When the capital stock exceeds $100,000, we have;

\displaystyle  \mathbf{\left[1000 \cdot  e^{0.1 \cdot t}} + C \right]^t_0} = 100,000

Which gives;

\displaystyle 1000 \cdot  e^{0.1 \cdot t}} - 1000 = 100,000

\displaystyle \mathbf{1000 \cdot  e^{0.1 \cdot t}}} = 100,000 + 1000 = 101,000

\displaystyle e^{0.1 \cdot t}} = 101

\displaystyle t = \frac{ln(101)}{0.1} \approx 46.15

The number of years before the capital stock exceeds $100,000 ≈ <u>46.15 years</u>.

Learn more investment function here:

brainly.com/question/25300925

6 0
2 years ago
Hi there can anyone help me with this question please
forsale [732]
Mean means average, so you would add the numbers up and divide by the amount of numbers in the set. 
4 0
3 years ago
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