Two cars leave towns 400 kilometers apart at the same time and travel toward each other. One car's rate is 14 kilometers per hou
r less than the other's. If they
meet in 2 hours, what is the rate of the slower car?
Do not do any rounding.
1 answer:
Answer:
Step-by-step explanation:
v*2+(v-14)*2=400
2v+2v-28=400
4v=400+28
4v=428
v=107 km/h
speed of slowest car=107-14=93 km/h
You might be interested in
Answer:
This moves f(x) 8 units to the left
Step-by-step explanation:
g(x) = f(x + 8)
y = f(x + C) C > 0 moves it left
This moves f(x) 8 units to the left
It depends, not exactly, because the techtonic plates aren't connected.
Its 81 centimeters because you round 5 and over. So nearest centimeter means 2 whole numbers which is 81
7(n - p) + 5p
7n - 7p + 5p
7n - 2p
