What is balance of trade and balance of payment?

LO 3.3When sales price decreases and all other variables are held constant, the break-even point will ________.

miss Akunina [59]

Answer:

increase

Explanation:

Break-even point is used to determine the minimum number of units a business needs to sell in order to fully cover the fixed costs. The break-even formula is below;

Break-even = Fixed cost / (Sale price - Variable cost)

If sales price (SP) decreases while keeping other factors; variable cost(VC) and fixed cost(FC) constant, the denominator amount will be smaller, making the break- even point to increase.

3 0

4 years ago

An oil refinery is located on the north bank of a straight river that is 3km wide. A pipeline is to be constructed from the refi

Mariulka [41]

Answer:

$6,598,076.21

Explanation:

<h2>THE KEY IS TO FIND OUT THE COST FUNCTION, the calculations are very easy!!!</h2><h2></h2><h3>In order to find the cost function, take a look at the drawing attached. </h3>

We can see the river (sort of) that is 3 km wide and the storage tanks on the other side of the river 8 km apart.

<h3 />

Laying pipes under (across) the river costs 1,000,000 the km & laying pipes over land costs 500,000 per km.

<h3 /><h3>So basically the cost function is 1,000,000 multiplied by something plus 500,000 multiplied by another something.</h3><h3 />

The distance across the river can be found by using Pythagoras Theorem. A side is 3 km the other is unknown, so we call it X. And it is equal to:

$\sqrt{3^{2} +x^{2}}=\\\sqrt{9 +x^{2}}$

And we multiply it by 1,000,000; the cost of laying pipe under the river, the we get:

$1000000\sqrt{9+x^{2}$

The distance over the land is (8-x), as we can see in the drawing. So we multiply it by its cost, 500,000. And we get 500,000(8-x).

So the cost function f(x) would be:

$f(x)=1000000\sqrt{9+x^{2}} + 500000(8-x)$

<h2>From here, we just have to differentiate and the derivative found must be equal to zero in order to minimize cost. </h2><h3>The value of x when the derivative is zero is plugged in the original function to get the cost.</h3><h3 /><h2>LET'S DO THIS</h2>

$f(x)=1000000\sqrt{9+x^{2}} + 500000(8-x)\\f(x)=1000000(9+x^{2})^{1/2}+4000000-500000x\\f'(x)=\frac{1}{2} 1000000(9+x^{2})^{-1/2}(2x)-500000\\\\f'(x)=\frac{1000000x}{\sqrt{9+x^2}} - 500000$

$f'(x)=\frac{1000000x}{\sqrt{9+x^2}} - 500000=0\\\frac{1000000x}{\sqrt{9+x^2}} = 500000\\\frac{2x}{\sqrt{9+x^2}} = 1\\2x={\sqrt{9+x^2}}\\4x^2=9+x^2\\3x^2=9\\x^2=3\\x=\sqrt{3} \\$

And we plug square root of 3 in the original cost function ad we get

$f(\sqrt{3} )=1000000\sqrt{9+x^{2}} + 500000(8-x)\\f(\sqrt{3})=1000000\sqrt{9+(\sqrt{3} )^{2}} + 500000(8-(\sqrt{3}))\\f(\sqrt{3})=1000000\sqrt{9+3} + 500000(8-(\sqrt{3}))\\f(\sqrt{3})=1000000\sqrt{12}+500000(6.27)\\f(\sqrt{3})=1000000(3.46)+500000(6.27)\\f(\sqrt{3})=3464101.62+3133974.60\\f(\sqrt{3})=6598076.21\\$

<h2>so the minimal cost is $6,598,076.21</h2><h2 /><h3 />

6 0

4 years ago

An auto analyst is conducting a satisfaction survey, sampling from a list of 10,000 new car buyers. The list includes 2,500 Ford

Ghella [55]

Answer:

No

Explanation:

Simple random sampling gives each member in the entire population an equal opportunity to be included in the sample. The technique removes bias in the selection procedure. It applies where a small number would adequately represent the entire population.

The procedure described in this case is a deviation of simple random sampling. It is stratified random sampling.

In stratified random sampling, the population is first divided into subgroups based on shared characteristics. The researcher uses simple random sampling to select representatives of each group in the sample population. The techniques ensure each group is fairly represented in the research.

Subdividing vehicles by their make is creating strata or subgroups.

3 0

3 years ago

Waterway Industries purchased a depreciable asset for $837300 on January 1, 2018. The estimated salvage value is $84000, and the

murzikaleks [220]

Answer:

$222,100

Explanation:

Cost = $837,300

Residual value = $84,000

Useful life = 9 years

Now,

Annual straight line depreciation = $\frac{Cost-Residual Value}{Useful life}$

Annual straight line depreciation = $\frac{837,300 - 84,000}{9}$

Annual straight line depreciation = $\frac{753,300}{9}$

Annual straight line depreciation = $83,700

Accumulated depreciation for three years i.e., 2018, 2019 and 2020 would be:

Accumulated depreciation = 3 × $83,700

Accumulated depreciation = $251,100

Book value (at the end of year 2020) = Cost - Accumulated depreciation

Book value (at the end of year 2020) = $837,300 - $251,100

Book value (at the end of year 2020) = $586,200

Revised useful life = 5 years

No. years asset has been used = 3 years

Remaining useful life = 2 years

Revised salvage value = $142,000

Therefore, depreciation expense for the remaining three year would be:

Revised depreciation expense = $\frac{Book value at the end of 2020 - Revised residual Value}{Remaining useful life}$

Revised depreciation expense = $\frac{586,200 - 142,000}{2}$

Revised depreciation expense = $\frac{444,200}{2}$

Revised depreciation expense = $222,100

5 0

3 years ago

The staff educator from the hospital’s respiratory unit is providing a public educational event. The educator is talking about h

Citrus2011 [14]

Answer:

Teaching strategies to reduce complications of existing diagnoses

Explanation:

Teaching strategies to reduce complications of existing diagnoses.

Health Promotion activities focus on preventing disease from developing that is primary prevention. And then screening to identify at early curable stage and this known as secondary prevention and reducing complications of existing or established medical diagnosis, which is the tertiary prevention.

8 0

3 years ago

What is balance of trade and balance of payment?​

What is balance of trade and balance of payment?