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Helga [31]
2 years ago
10

fruit salad for 5 people needs 400g of melon, 120g of mango, 0.3kg of banana and 0.45kg of grapes. How much will it weigh in gra

ms if it was made for 15 people?​
Mathematics
1 answer:
tamaranim1 [39]2 years ago
5 0
The equation you would use for this problem would be x=(400g)+(120g)+(300g)+(450g)x(3)

x=2170g for 15 people
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Determine the standard variation of the data below. (1, 2, 3, 4, 5)
Ne4ueva [31]
Calculate for the mean/ average of the given numbers:
 
                             μ = (1 + 2 + 3 + 4 + 5) / 5 = 3

Then, we calculate for the summation of the squares of differences of these numbers from the mean, S
 
                             S  = (1 - 3)² + (2 - 3)² + (3 - 3)² + (4 - 3)² + (5 - 3)²
                                S = 10

Divide this summation by the number of items and take the square root of the result to get the standard deviation.

                              SD = sqrt (10 / 5) = sqrt 2  
                                    SD = 1.41

Thus, the standard deviation of the given is equal to 1.41. 
              
                            
8 0
3 years ago
Read 2 more answers
PLEASEEE HELP THANK YOU!
Fittoniya [83]

Answer:

Hi Sophia! The answer is the option 3!

Step-by-step explanation:

Check the picture!

8 0
3 years ago
Peyton is making a recipe that requires 2 cups of water and 6 cups of flour.what is the ratio as a fraction
lisabon 2012 [21]
1/3 is the ratio of cups of water to cups of flour as a fraction (simplified)
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3 years ago
Writer y=3/4x+8 in standard form
Harman [31]

Answer:

3x - 4y = -32

Step-by-step explanation:

6 0
3 years ago
Is there any systematic tendency for part-time college faculty to hold their students to different standards than do full-time f
alexandr1967 [171]

Answer:

H0 : μ1 - μ2 = 0

H1 : μ1 - μ2 ≠ 0

-1. 34

0.1837

Step-by-step explanation:

Full time :

n1 = 125

x1 = 2.7386

s1 = 0.65342

Part time :

n2 = 88

x2 = 2.8439

s2 = 0.49241

H0 : μ1 - μ2 = 0

H1 : μ1 - μ2 ≠ 0

Test statistic :

The test statistic :

(x1 - x2) / sqrt[(s1²/n1 + s2²/n2)]

(2.7386 - 2.8439) / sqrt[(0.65342²/125 + 0.49241²/88)]

−0.1053 / sqrt(0.0034156615712 + 0.0027553)

-0.1053 /0.0785554

= - 1.34

Test statistic = - 1.34

The Pvalue :

Using df = smaller n - 1 = 88 - 1 = 87

Pvalue from test statistic score ;

Pvalue = 0.1837

Pvalue > α ; We fail to reject the null and conclude that the GPA does not differ.

At α = 0.01 ; the result is insignificant

6 0
2 years ago
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