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2 years ago

Which expression is equivalent to 2(u+4)? 2u+8 8u+2 8u 6u

Mathematics

1 answer:

irga5000 [103]2 years ago

4 0

Answer:

2u + 8

General Formulas and Concepts:

Pre-Algebra

Distributive Property

Step-by-step explanation:

Step 1: Define

2(u + 4)

Step 2: Expand

Distribute 2: 2(u) + 2(4)
Multiply: 2u + 8

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Claire is building a dollhouse where 11 inch on the plans is equivalent to 55 inches on the actual dollhouse. Scale Factor If

Liula [17]

Answer:

1 : 5 ;

6.5 inches

Step-by-step explanation:

Given that:

11 inch on plan = 55 in actual

The scale factor here is :

11 : 55

1 : 5 ( 1 inch on plan represents 5 inches the actual house)

If the house is 32.5 inches tall

The height in inches of the house on the plan will be:

Actual Height of house / 5

32.5 / 5 = 6.5 inches

3 0

2 years ago

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What is the equation for a line passing through (-2,3) and perpendicular to y= -1/2+1 ?

nata0808 [166]

Answer:

$y=2x+7$

Step-by-step explanation:

The correct question is

what is the equation for a line passing through (-2,3) and perpendicular to y= -1/2x+1 ?

Remember

If two lines are perpendicular, then their slopes are opposite reciprocal (the product of their slopes are equal to -1)

The slope of the given line is m=-1/2

the opposite reciprocal is m=2

Find the equation of the line in point slope form

$y-y1=m(x-x1)$

we have

$m=2\\point\ (-2,3)$

substitute

$y-3=2(x+2)$

Convert to slope intercept form

$y=mx+b$

isolate the variable y

$y-3=2x+4$

$y=2x+4+3$

$y=2x+7$

3 0

3 years ago

How do I calculate 1/5 of 125

Brrunno [24]

Answer:

You do 1/5 x 125 which equals 25

Step-by-step explanation:

4 0

3 years ago

if you have a box of candy that is 8 inches long 5 inches wide and 2 inches tall how much space do you have for candy

stiv31 [10]

8 x 5 x 2 = 80 square cubits

4 0

3 years ago

Read 2 more answers

Each year for 4 years, a farmer increased the number of trees in a certain orchard by of the number of trees in the orchard the

Neko [114]

Answer:

The number of trees at the begging of the 4-year period was 2560.

Step-by-step explanation:

Let’s say that x is number of trees at the begging of the first year, we know that for four years the number of trees were incised by 1/4 of the number of trees of the preceding year, so at the end of the first year the number of trees was $x+\frac{1}{4} x=\frac{5}{4} x$ , and for the next three years we have that

Start End

Second year $\frac{5}{4}x$ -------------- $\frac{5}{4}x+\frac{1}{4}(\frac{5}{4}x) =\frac{5}{4}x+ \frac{5}{16}x=\frac{25}{16}x=(\frac{5}{4} )^{2}x$

Third year $(\frac{5}{4} )^{2}x$ ------------- $(\frac{5}{4})^{2}x+\frac{1}{4}((\frac{5}{4})^{2}x) =(\frac{5}{4})^{2}x+\frac{5^{2} }{4^{3} } x=(\frac{5}{4})^{3}x$

Fourth year $(\frac{5}{4})^{3}x$ -------------- $(\frac{5}{4})^{3}x+\frac{1}{4}((\frac{5}{4})^{3}x) =(\frac{5}{4})^{3}x+\frac{5^{3} }{4^{4} } x=(\frac{5}{4})^{4}x.$

So the formula to calculate the number of trees in the fourth year is

$(\frac{5}{4} )^{4} x,$ we know that all of the trees thrived and there were 6250 at the end of 4 year period, then

$6250=(\frac{5}{4} )^{4}x$ ⇒ $x=\frac{6250*4^{4} }{5^{4} }= \frac{10*5^{4}*4^{4} }{5^{4} }=2560.$

Therefore the number of trees at the begging of the 4-year period was 2560.

7 0

3 years ago