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saul85 [17]
3 years ago
14

What is 758 x 8494 thank you

Mathematics
2 answers:
Step2247 [10]3 years ago
8 0

Answer:

6438452

Step-by-step explanation:

have a good day /night

may i please have a branlliest

GarryVolchara [31]3 years ago
5 0

Answer:

the answer would be 6438452

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Water flows straight down from an open faucet. The cross-sectional area of the faucet is 1.00 × 10 − 4 m², and the speed of the
Setler79 [48]

Answer:A_2=0.349\times 10^{-4} m^2

Step-by-step explanation:

Given

velocity v_1=0.72 m/s

Area of cross-section A_1=1\times 10^{-4} m^2

velocity after Falling 0.19 m

v_2^2-v_1^2=2g\cdot h

v_2^2=v_1^2+2g\cdot h

v_2^2=(0.72)^2+2\times 9.8\times 0.19

v_2^2=0.518+3.724

v_2=\sqrt{4.24}

v_2=2.05 m/s

conserving Flow

A_1v_1=A_2v_2

1\times 10^{-4}\times 0.72=A_2\times 2.05

A_2=0.349\times 10^{-4} m^2

8 0
3 years ago
What is the slope of the line graphed below?<br><br> A. 1<br> B. -1<br> C. 0<br> D. Undefined
Lena [83]
The slope of the line is 1
7 0
3 years ago
Read 2 more answers
Michael paid $11.48 for sliced cheese at the deli counter. The cheese cost $3.28 per pound. How much cheese did he buy?
Charra [1.4K]
Michael bought 3.5 lbs of cheese 

Divide 11.48 by 3.28
3 0
2 years ago
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The side of a cube is 3^4 centimeters long. What is the volume of the cube?​
labwork [276]

Step-by-step explanation:

v=s^3 s=3^4=81

v=(81)^3

v=531,441 cm^3

7 0
3 years ago
a pyramid whose altitude is 5ft weighs 800lbs. at what distance from its vertex must it be cut by a plane parallel to its base s
slavikrds [6]

A structure which has a square base and four triangular sides meeting at a point is called pyramid.

At distance of 3.97 feet from its vertex , pyramid is cut by plane  so that the two solids of equal weight will be formed.

<u>It is assumed that weight of pyramid is proportional to its volume.</u>

So,   w  = k V , where V is volume of original pyramid and v is volume of small pyramid and k is constant.

Let us consider that at h  distance,  pyramid is cut from its vertex. So a small pyramid is also formed.

Assume that base area of original pyramid is A and base of small pyramid is a.

Volume of original pyramid is,   V= \frac{1}{3}  *A* 5

So, weight of original pyramid,  W = k *(\frac{1}{3}  *A* 5) = 800

Volume of small pyramid is,  v = \frac{1}{3}* a* h

So, weight of small pyramid, w = k*(\frac{1}{3}* a* h)=400

<u>Since, base and height of small pyramid and original pyramid are in proportion.</u>

So,  \frac{a}{A}  = (\frac{h}{5}) ^{2}

       a = (\frac{h}{5} )^{2}A

Substituting value of a in  equation k*(\frac{1}{3}* a* h)=400

So, k*(\frac{1}{3}* \frac{h^{2} }{25}A * h)=400

       (k*\frac{1}{3}* A*5)*\frac{1}{5} *\frac{h^{2} }{25} * h)=400

Since, (k *\frac{1}{3}  *A* 5) = 800, substitute in above equation.

    So, 800*\frac{h^{3} }{125}=400\\\\h^{3}=\frac{125}{2}\\\\h=\sqrt[\frac{1}{3} ]{62.5}\\\\h=3.97 feet

Learn more:

brainly.com/question/17950304

6 0
2 years ago
Read 2 more answers
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