Multiplying both sides of an equation by the same number keeps the equation true. In this example, both sides are multiplied by 3, so the equation isn't changed.
(x-4)² + (x-2)² = x²
(x² - 8x + 16 ) + (x² - 4x + 4) = x
2x² -12x + 20 = x
2x²-12x + 20 - x = 0
2x² - 13x + 20 = 0
(2x-5) (x-4) = 0
2x-5 = 0
2x = 5
x = ⁵/₂
x-4 = 0
x = 4
so x₁ = ⁵/₂ , and x₂ = 4
Answer:
2
Step-by-step explanation:
If you divide 0 by any number you will get 0
If you will substitute x for 2 you will have:
2-2/2+2=0/4=0
That is where the line crosses the x axis or where y=0
0=-16x^2+22x+3
we gon do grouping
ac method
-16 times 3=-48
what 2 numbers multiply to get -48 and add to get 22
-2 and 24
0=-16x^2-2x+24x+3
group
0=(-16x^2-2x)+(24x+3)
undistribute
0=-2x(8x+1)+3(8x+1)
undistribute
0=(8x+1)(-2x+3)
set eaqual to 0
8x+1=0
8x=-1
x=-1/8
-2x+3=0
3=2x
3/2=x
x intercepts ate x=-1/8 and x=3/2
