Solution:
Population in the city= 10,000
As genetic condition affects 8% of the population.
8 % of 10,000
As, it is also given that, there is an error rate of 1% for condition (i.e., 1% false negatives and 1% false positives).
So, 1% false negatives means out of 800 tested who are found affected , means there are chances that 1% who was found affected are not affected at all.
So, 1% of 800 
Also, 1% false positives means out of 10,000 tested,[10,000-800= 9200] who are found not affected , means there are chances that 1% who was found not affected can be affected also.
So, 1% of 9200 
1. Has condition Does not have condition totals = 800
2. Test positive =92
3. Test negative =8
4. Total =800 +92 +8=900
5. Probability (as a percentage) that a person has the condition if he or she tests positive= As 8% are found positive among 10,000 means 9200 are not found affected.But there are chances that out of 9200 , 1% may be affected
that is Probability equal to 0.01 or 1%.
Answer:
The <em>y </em>-intercept is: (0,−2.5)
The <em>x </em>-intercept is: (−2,0)
Step-by-step explanation:
Answer:
-3 or decreasing by 3
Step-by-step explanation:
To find the average change, you only care about the first and last point which would be (3,17) and (8,2)
the overall change during that time is 2-17=-15 (for the f(x) side )
the overall change during that time is 8-3=5(for the x side)
all we have to do is -15/5=-3
therefore the average rate of change is -3
This question is referred to two similar triangles.
One triangle has sides x and x - 2.
The other triangle has the respective sides x + x + 5 and x - 2 + x + 1
Then you can state a proportionality relation between the sides>
[x + x + 5] / x = [x - 2 + x + 1] / [x - 2]
=> [2x + 5] / x = [2x - 1] / [x - 2]
=> (2x + 5)(x - 2) = (2x - 1)x
=> 2x^2 - 4x + 5x - 10 = 2x^2 - x
=> x - 10 = - x
=> 2x = 10
=> x = 10 / 2
=> x = 5
Answer: x = 5
Answer:
4x + 2y = 7
Step-by-step explanation:
The standard form equation goes as follows: Ax + By = C
We know what A, B, and C is so all we need to do is fill them in.
