The distance between any 2 points P(a,b) and
Q(c,d) in the coordinate plane, is given by the formula:<span>
<span>
</span></span>
Using this formula we calculate the distances |PA|, |PB|, |PC|, |PD| and |PE| and compare to 5.





Answer: B and D
9514 1404 393
Answer:
A √2 is an irrational number
Step-by-step explanation:
A: √2 ≈ 1.4142135623730950488... an infinite non-repeating decimal (irrational)
B: √4 = 2 (rational)
C: ∛8 = 2 (rational)
D: √16 = 4 (rational)
Answer:
ΔABX and ΔEDX
Step-by-step explanation:
Given: AX ≅ EX
BX ≅ DX
SAS implies a congruent relation with respect to Side-Angle-Side between the two required triangle.
AX ≅ EX (given)
BX ≅ DX (given)
<BXA ≅ <DXE (vertical opposite angles)
Therefore,
ΔABX ≅ ΔEDX (Side-Angle-Side, SAS, congruence property)
1 revolution is 2xPixr
it is 2xPixr=2x 3.14 x 15=94. 2cm
for 4 revolutions
it is 94. 2cmx4= <span>376.8 cm
the answer is C </span><span>: 376.8 cm</span>
Answer:
>
Step-by-step explanation:
.386 is greater than .368