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Yuri [45]
3 years ago
14

Evaluate the expression using the values in the left column to complete the table

Mathematics
1 answer:
egoroff_w [7]3 years ago
7 0

Answer/Step-by-step explanation:

A. 4b + 3b

Using b = 2

4(2) + 3(2) = 8 + 6 = 14

Using b = 4

4(4) + 3(4) = 16 + 12 = 28

Using b = 6

4(6) + 3(6) = 24 + 18 = 42

Using b = 8

4(8) + 3(8) = 32 + 24 = 56

Using b = 10

4(10) + 3(10) = 40 + 30 = 70

Using b = 2

4(12) + 3(12) = 48 + 36 = 84

B. 3(x - 2)

Using x = 3

3(3 - 2) = 3(1) = 3

Using x = 5

3(5 - 2) = 3(3) = 9

Using x = 7

3(7 - 2) = 3(5) = 15

Using x = 9

3(9 - 2) = 3(7) = 21

Using x = 11

3(11 - 2) = 3(9) = 27

Using x = 13

3(13 - 2) = 3(11) = 33

C. 5(4a - 1)

Using a = 2

5(4(2) - 1) = 5(8 - 1) = 5(7) = 35

Using a = 3

5(4(3) - 1) = 5(12 - 1) = 5(11) = 55

Using a = 4

5(4(4) - 1) = 5(16 - 1) = 5(15) = 75

Using a = 5

5(4(5) - 1) = 5(20 - 1) = 5(19) = 95

Using a = 6

5(4(6) - 1) = 5(24 - 1) = 5(23) = 115

Using a = 7

5(4(7) - 1) = 5(28 - 1) = 5(27) = 135

D. 6y - 2y + 4

Using y = 2

6(2) - 2(2) + 4 = 12 - 4 + 4 = 12

Using y = 3

6(3) - 2(3) + 4 = 18 - 6 + 4 = 18 - 2 = 16

Using y = 5

6(5) - 2(5) + 4 = 30 - 10 + 4 = 30 - 6 = 24

Using y = 10

6(10) - 2(10) + 4 = 60 - 20 + 4 = 60 - 16 = 44

Using y = 8

6(8) - 2(8) + 4 = 48 - 16 + 4 = 48 - 12 = 36

Using y = 6

6(6) - 2(6) + 4 = 36 - 12 + 4 = 36 - 8 = 28

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Nataly [62]
The fraction 36/180 can be recuced to 1/5 because 36 divided by 36 is 1 and 180 divided by 36 is 5 hope it helped :)
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3 years ago
HELP IM BEING TIMED!!
grigory [225]

Answer:

Value of x is 8

Step-by-step explanation:

Given:

\sqrt{\frac{896z^{15}}{225z^6} }=\frac{xz^4}{15}  \sqrt{14z}\\\\Computation: \\\\From\ squaring\ both\ side\\\\ {\frac{896z^{15}}{225z^6} }=\frac{x^2z^8}{225} ({14z})\\\\896z^9=14x^2z^9\\\\896=14x^2\\\\64=x^2\\\\x = 8

So, Value of x is 8

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3 years ago
Please help, thank you! Correct answer gets brainliest!
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Answer:

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Remember that graphically, the solutions for a system of equations are all the points where the graphs intersect.

In the graph of the system of equations, we see that the they intersect once at (-1, 3) and again at (1, 5).

Therefore, our two solutions to the system are (-1, 3) and (1, 5).

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