Answer:
The claim that the scores of UT students are less than the US average is wrong
Step-by-step explanation:
Given : Sample size = 64
Standard deviation = 112
Mean = 505
Average score = 477
To Find : Test the claim that the scores of UT students are less than the US average at the 0.05 level of significance.
Solution:
Sample size = 64
n > 30
So we will use z test

Formula : 


Refer the z table for p value
p value = 0.9772
α=0.05
p value > α
So, we accept the null hypothesis
Hence The claim that the scores of UT students are less than the US average is wrong
450/313*10.5 = 15.09.... which is approx is 15
Volume of a cone = pi * r² * (h/3)
If your diameter is 2, then take half of that for the radius; your radius is 1
Now plug in your given info:
V = pi * (1)² * (7/3)
= pi * 1 * (7/3)
= 7pi / 3
V ≈ 7.3304
Your answer is option D.