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3 years ago

9

create a linear equation for a word problem dealing with income and total masks. If we know that each mask will be sold for 11.5

0 and the cost of the mask the company will pay is 3.50 and the total amount the company has to invest is 50,000.

1 answer:

GarryVolchara [31]3 years ago

4 0

Answer:

50,000=11.50x+3.50

hope that helps

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Solve the given equation.<br><br><br><br> s - 19 = 12

Viktor [21]

Answer:

s=31

Step-by-step explanation:

hi again so what you are gonna do is find out the opposite of subtraction which is addition then you are gonna do the opposite..so add 19 and 12 together then your sum would be 31.....to check your answer you must subtract 31 from 19 and then you get 12....so therefore s=31

hope you are getting a better understanding!

6 0

3 years ago

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About 13% of the population of a large country is nervous around strangersnervous around strangers. If two people are randomly

Molodets [167]

Answer:

1.69% probability both are nervous around strangers.

24.31% probability at least one is nervous around strangers.

Step-by-step explanation:

For each person, there are only two possible outcomes. Either they are nervous around strangers, or they are not. The people are chosen randomly, which means that the probability of a person being nervous around strangers is independent from other people. So we use the binomial probability distribution to solve this problem.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

In which $C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And p is the probability of X happening.

About 13% of the population of a large country is nervous around strangers.

This means that $p = 0.13$ .

Two people are randomly selected

This means that $n = 2$ .

What is the probability both are nervous around strangers?

This is $P(X = 2)$

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 2) = C_{2,2}.(0.13)^{2}.(0.87)^{0} = 0.0169$

1.69% probability both are nervous around strangers.

What is the probability at least one is nervous around strangersnervous around strangers?

This is $P(X \geq 1)$

$P(X \geq 1) = P(X = 1) + P(X = 2)$

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 1) = C_{2,1}.(0.13)^{1}.(0.87)^{1} = 0.2262$

$P(X = 2) = C_{2,2}.(0.13)^{2}.(0.87)^{0} = 0.0169$

$P(X \geq 1) = P(X = 1) + P(X = 2) = 0.2262 + 0.0169 = 0.2431$

24.31% probability at least one is nervous around strangers.

3 0

3 years ago

Simplify.<br><br> 4n + 12 + 7n<br><br> 16n + 7<br> 23n<br> 11n + 12<br> 4n + 19

DENIUS [597]

4n + 12 + 7n

To simplify this expression, combine like terms.

The like terms are 4n and 7n, so add them together.

11n + 12 is your answer.

6 0

4 years ago

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Pls help I will give u brainlyist

zimovet [89]

Answer:

I remember it was Triangular prism or something

Step-by-step explanation:

2 triangles on top

and the sides with rectangle.

5 0

3 years ago

Shanti wrote the predicted values for a data set using the line of best fit y = 2.55x – 3.15. She computed two of the residual v

svet-max [94.6K]

<span>Residual value is the difference between the observed value of the dependent variable (y) and the predicted value (ŷ) in a data set.

i.e. Residual value = given value - predicted value

From the table, the residual value corresponding to a has 4.1 as the given value and 4.5 as the predicted value.
Therefore, a = 4.1 - 4.5 = -0.4

Similarly, </span><span>the residual value corresponding to b has 7.2 as the given value and 7.05 as the predicted value.
Therefore, b = 7.2 - 7.05 = 0.15
</span>
Therefore, a = -0.4 and b = 0.15

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3 years ago

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