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3 years ago

Analyze the diagram below and complete the instructions that follow. / Find /. A. 45° B. 80° C. 90° D. 100°

Mathematics

2 answers:

Mademuasel [1]3 years ago

5 0

Answer: The answer is 80

yawa3891 [41]3 years ago

4 0

I think is B 80 c

Any non zero expression raised to the power of 0 equals 1

80c x 1

Y= 80c x 9000.1

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Help me please due tomorrow!!

Vladimir79 [104]

4 2/3 into improper fracking would be 14/3 now times 3 , 3 and 3 go into 1 so your left with 24 so THATS the answer in other words it would be 42/3 which goes into 14 times:)

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3 years ago

Suppose you bought supplies. Three rolls of streamers and 15 party hats cost $30. Later, you bought 2 rolls of streamers ad 4 pa

Zolol [24]

Since 30÷15 is 2 you now know each party hat is 2 dollars. Now we know that and we can easily find out how much a roll of streamer is. 11-(4x2)=3. 3÷2=1.5. One roll of streamer is $1.50 and one party hat is $2. I'm pretty sure I did this right lol I hope it helps

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3 years ago

Solve for the values of x and y.

Tasya [4]

Answer:

We can’t solve for x and y

Step-by-step explanation:

5 0

2 years ago

Read 2 more answers

A bag contains white marbles and red marbles, 90 in total. The number of white marbles is 6 less than 5 times the number of red

Gelneren [198K]

Answer:

W = 72

Step by step explanation:

White = W

Red = R

W + R = 90

Write an equation

W = 5R - 6

Substitute

5R - 6 = 90

Add 6 to both sides of the equation

5R = 90

Simplify

90 ÷ 5 = 18

R = 18

90 - 18 = W

W = 72

Hope this was useful to you!

8 0

3 years ago

Write the equation of the quadratic function whose graph passes through <img src="https://tex.z-dn.net/?f=%28-3%2C2%29" id="TexF

blagie [28]

Answer:

$f(x)=x^2+3x+2$

Step-by-step explanation:

We want to write the equation of a quadratic whose graph passes through (-3, 2), (-1, 0), and (1, 6).

Remember that the standard quadratic function is given by:

$f(x)=ax^2+bx+c$

Since it passes through the point (-3, 2). This means that when $x=-3$ , $f(x)=f(-3)=2$ . Hence:

$f(-3)=2=a(-3)^2+b(-3)+c$

Simplify:

$2=9a-3b+c$

Perform the same computations for the coordinates (-1, 0) and (1, 6). Therefore:

$0=a(-1)^2+b(-1)+c \\ \\0=a-b+c$

And for (1, 6):

$6=a(1)^2+b(1)+c\\\\ 6=a+b+c$

So, we have a triple system of equations:

$\left\{ \begin{array}{ll} 2=9a-3b+c &\\ 0=a-b+c \\6=a+b+c \end{array} \right.$

We can solve this using elimination.

Notice that the b term in Equation 2 and 3 are opposites. Hence, let's add them together. This yields:

$(0+6)=(a+a)+(-b+b)+(c+c)$

Compute:

$6=2a+2c$

Let's divide both sides by 2:

$3=a+c$

Now, let's eliminate b again but we will use Equation 1 and 2.

Notice that if we multiply Equation 2 by -3, then the b terms will be opposites. So:

$-3(0)=-3(a-b+c)$

Multiply:

$0=-3a+3b-3c$

Add this to Equation 1:

$(0+2)=(9a-3a)+(-3b+3b)+(c-3c)$

Compute:

$2=6a-2c$

Again, we can divide both sides by 2:

$1=3a-c$

So, we know have two equations with only two variables:

$3=a+c\text{ and } 1=3a-c$

We can solve for a using elimination since the c term are opposites of each other. Add the two equations together:

$(3+1)=(a+3a)+(c-c)$

Compute:

$4=4a$

Solve for a:

$a=1$

So, the value of a is 1.

Using either of the two equations, we can now find c. Let's use the first one. Hence:

$3=a+c$

Substitute 1 for a and solve for c:

$\begin{aligned} c+(1)&=3 \\c&=2 \end{aligned}$

So, the value of c is 2.

Finally, using any of the three original equations, solve for b:

We can use Equation 3. Hence:

$6=a+b+c$

Substitute in known values and solve for b:

$6=(1)+b+(2)\\\\6=3+b\\\\b=3$

Therefore, a=1, b=3, and c=2.

Hence, our quadratic function is:

$f(x)=x^2+3x+2$

5 0

3 years ago