Answer:
<8
Step-by-step explanation:
From the diagram, Corresponding angles are congruent that is Corresponding angles are equal in measure. From the diagram shown, the angle corresponding to <4 is <8 since they are located at the same position on both parallel lines that is right below (both at the top and bottom based on geometry )
what is the maximum, minimum, quartile 1, median, quartile 3, range, interquartlie range of these numbers " 46,48,50,52, and 54"
Gekata [30.6K]
Min=46
Max=54
1 quartile= 48
Median=50
3 quartile=52
46/48 percent is 95.83%
Answer:
Exact form: ![\sin{(6x)} = \frac{8}{9}](https://tex.z-dn.net/?f=%5Csin%7B%286x%29%7D%20%3D%20%5Cfrac%7B8%7D%7B9%7D)
Decimal form: ![\sin{(6x)} = 0.8889](https://tex.z-dn.net/?f=%5Csin%7B%286x%29%7D%20%3D%200.8889)
The solution for x is: The solution for x is of 10.455º
Step-by-step explanation:
We are given the following equation:
![8 = 9\sin{(6x)}](https://tex.z-dn.net/?f=8%20%3D%209%5Csin%7B%286x%29%7D)
Placing into the desired format, the exact format is:
![\sin{(6x)} = \frac{8}{9}](https://tex.z-dn.net/?f=%5Csin%7B%286x%29%7D%20%3D%20%5Cfrac%7B8%7D%7B9%7D)
In the decimal part, we divide 8 by 9. So
![\sin{(6x)} = 0.8889](https://tex.z-dn.net/?f=%5Csin%7B%286x%29%7D%20%3D%200.8889)
Solving for x:
We apply the inverse sine. So
![\sin^{-1}{\sin{(6x)}} = \sin^{-1}{0.8889}](https://tex.z-dn.net/?f=%5Csin%5E%7B-1%7D%7B%5Csin%7B%286x%29%7D%7D%20%3D%20%5Csin%5E%7B-1%7D%7B0.8889%7D)
![6x = 62.73](https://tex.z-dn.net/?f=6x%20%3D%2062.73)
![x = \frac{62.73}{6}](https://tex.z-dn.net/?f=x%20%3D%20%5Cfrac%7B62.73%7D%7B6%7D)
![x = 10.455](https://tex.z-dn.net/?f=x%20%3D%2010.455)
The solution for x is of 10.455º
Answer:
B) Vertex (1,2), maximum
Step-by-step explanation:
First, determine if the graph has a maximum or a minimum value. Since the graph opens downwards, it has a <u>maximum</u> value.
The maximum is the point that has the greatest y value. We can see that the greatest y value is at
. Going down two units from that spot, we can see that the x value is at
. We can plug those into the vertex form,
. By plugging in we get the point
.