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2 years ago

Please please help image attached it’s ap calc ab

Mathematics

1 answer:

vaieri [72.5K]2 years ago

8 0

The average rate of change of a function f(x) over some interval [a, b] is the difference quotient,

$\dfrac{f(b)-f(a)}{b-a}$

which corresponds to the slope of the line connecting the points (a, f(a)) and (b, f(b)) in the graph of f(x).

Given f(x) = 3x² - x³ (correct me if I'm wrong, the exponents look cut off in your screenshot), the average rate of change on [1, 5] is

$\dfrac{f(5)-f(1)}{5-1}=\dfrac{(3\cdot5^2-5^3)-(3\cdot1^2-1^3)}4 = \dfrac{75-125-3+1}4 = \boxed{-13}$

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Just number 2 please

Nezavi [6.7K]

Answer:

It has 3 sides and the measure is 3

Step-by-step explanation:

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3 years ago

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The difference in the x-coordinates of two points is 3, and the difference in the y-coordinates of the two points is 6. What is

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3 years ago

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1-73.

cricket20 [7]

36inch - 2 feet

72inch - 4 feet

144inch - 8 feet

18 X 2 = 36

1 + 1 = 2

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3 years ago

Can someone help me with this math question?

Triss [41]

It would be 19

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3 years ago

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Which expression is equivalent to (x superscript four-thirds baseline x superscript two-thirds Baseline ) superscript one-third

Andrei [34K]

<h3>The equivalent expression is:</h3>

$(x^{\frac{4}{3}}x^{\frac{2}{3}})^{\frac{1}{3}} = x^{\frac{2}{3}$

Solution:

Given expression is:

$\displaystyle (x^{\frac{4}{3}}x^{\frac{2}{3}})^{\frac{1}{3}}$

We have to find the equivalent expression

We can simplify the above expression using law of exponents

Use the following law of exponents:

$a^m \times a^n = a^{m+n}$

Therefore,

$\displaystyle (x^{\frac{4}{3}}x^{\frac{2}{3}})^{\frac{1}{3}} = (x^{\frac{4}{3}+\frac{2}{3}})^{\frac{1}{3}}\\\\Simplify\\\\\displaystyle (x^{\frac{4}{3}}x^{\frac{2}{3}})^{\frac{1}{3}} = (x^2)^\frac{1}{3}$

Use another law of exponent

$(a^m)^n = a^{mn}$

Therefore,

$(x^{\frac{4}{3}}x^{\frac{2}{3}})^{\frac{1}{3}} = x^{\frac{2}{3}$

Thus the equivalent expression is found

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3 years ago

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Please please help *image attached* it’s ap calc ab

Please please help image attached it’s ap calc ab