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BARSIC [14]
2 years ago
11

Please help! i’ve been stuck on this for over 10 minutes.

Mathematics
1 answer:
Natali [406]2 years ago
3 0
Pick two points in the graph
(-2,0) and (3,4)
Slope: (y2-y1)/(x2-x1)
(4-0)/(3+2)
Slope is 4/5
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Cookies are on sale! Today each cookie costs $0.75, less than the normal price. Right now if you buy 7 of them it will only cost
Sophie [7]
Equation : c = (2.80 / 7) + 0.75

Normal price of each cookie:
c = (2.80 / 7) + 0.75
c = 0.4 + 0.75
c = $1.15
3 0
3 years ago
A circle passes through points A(7,4), B(10,6), C(12,3). Show that AC must be the diameter of the circle.
Artist 52 [7]

so we have three points, A, B and C, if indeed AC is the diameter of the circle, then half the distance of AC is its radius, and the midpoint of AC is the center of the circle, morever, since B is also on the circle, the distance from B to the center must be the same radius distance.

in short, half the distance of AC must be equals to the distance of B to the midpoint of AC, if indeed AC is the diameter.

\bf ~~~~~~~~~~~~\textit{middle point of 2 points } \\\\ A(\stackrel{x_1}{7}~,~\stackrel{y_1}{4})\qquad C(\stackrel{x_2}{12}~,~\stackrel{y_2}{3}) \qquad \left(\cfrac{ x_2 + x_1}{2}~~~ ,~~~ \cfrac{ y_2 + y_1}{2} \right) \\\\\\ \left( \cfrac{12+7}{2}~~,~~\cfrac{3+4}{2} \right)\implies \left( \cfrac{19}{2}~~,~~\cfrac{7}{2} \right)=M\impliedby \textit{center of the circle}

now, let's check the distance from say A to the center, and check the distance of B to the center, if it's indeed the center, they'll be the same and thus AC its diameter.

\bf ~~~~~~~~~~~~\textit{distance between 2 points} \\\\ A(\stackrel{x_1}{7}~,~\stackrel{y_1}{4})\qquad M(\stackrel{x_2}{\frac{19}{2}}~,~\stackrel{y_2}{\frac{7}{2}})\qquad \qquad d = \sqrt{( x_2- x_1)^2 + ( y_2- y_1)^2} \\\\\\ AM=\sqrt{\left( \frac{19}{2}-7 \right)^2+\left( \frac{7}{2}-4 \right)^2} \\\\\\ AM=\sqrt{\left( \frac{5}{2}\right)^2+\left( -\frac{1}{2} \right)^2}\implies \boxed{AM\approx 2.549509756796392} \\\\[-0.35em] ~\dotfill

\bf ~~~~~~~~~~~~\textit{distance between 2 points} \\\\ B(\stackrel{x_1}{10}~,~\stackrel{y_1}{6})\qquad M(\stackrel{x_2}{\frac{19}{2}}~,~\stackrel{y_2}{\frac{7}{2}}) \\\\\\ BM=\sqrt{\left( \frac{19}{2}-10 \right)^2+\left( \frac{7}{2}-6 \right)^2} \\\\\\ BM=\sqrt{\left( -\frac{1}{2}\right)^2+\left( -\frac{5}{2} \right)^2}\implies \boxed{BM\approx 2.549509756796392}

6 0
3 years ago
Atevery bus station, busses depart at a rate of 3 every 10 minutes. At this rate, how many buses would you expect to depart in o
Ber [7]
Rate of 3 every 10 minutes.

In 10 minutes there are 3 buses.

In  1 minute    it is        (3/10).     For 1 hour = 60 minutes.

For 60 minutes  =  3/10  * 60  =  18.

18 buses.
7 0
3 years ago
Find the distance travelled in 1 h 40 min at a speed of 90 km/h
Mariulka [41]
90 km/h is your constant.
1h 40m - 1h since we have 90 km/h.
2/3 of 90 is what we need to find for the 40 min, since 40m/60m = 2/3.
60 is 2/3 of 90.
90 + 60 = 150.
Your distance traveled is 150km.
5 0
3 years ago
Use a calculator to find a decimal approximation for the following trigonometric function sin 28°48
Bumek [7]

The decimal approximation for the trigonometric function sin 28°48' is

Given the trigonometric function is sin 28°48'

The ratio between the adjacent side and the hypotenuse is called cos(θ), whereas the ratio between the opposite side and the hypotenuse is called sin(θ). The sin(θ) and cos(θ) values for a given triangle are constant regardless of the triangle's size.

To solve this, we are going to convert 28°48' into degrees first, using the conversion factor 1' = 1/60°

sin (28°48') = sin(28° ₊ (48 × 1/60)°)

= sin(28° ₊ (48 /60)°)

= sin(28° ₊ 4°/5)

= sin(28° ₊ 0.8°)

= sin(28.8°)

= 0.481753

Therefore sin (28°48') is 0.481753.

Learn more about Trigonometric functions here:

brainly.com/question/25618616

#SPJ9

5 0
1 year ago
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