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mina [271]
3 years ago
11

An element with mass 490 grams decays by 28.6% per minute. How much of the element is remaining after 16 minutes, to the nearest

10th of a gram?
Mathematics
1 answer:
agasfer [191]3 years ago
5 0

Answer:

2.2 grams

Step-by-step explanation:

We can use the compound decay formula shown below to solve this:

F=P(1-r)^t

Where

F is the final amount (what we want to find)

P is the present amount (490 grams)

r is the rate of decay, in decimal (28.6% = 28.6/100 = 0.286)

t is the time in minutes (16)

Substituting, we get:

F=P(1-r)^t\\F=490(1-0.286)^{16}\\F=490(0.714)^{16}\\F=2.2355

So, after 16 minutes, 2.2355 grams will be remaining.

<em>Rounded to nearest tenth of a gram (1 decimal place) = </em><em>2.2 grams remaining</em>

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Triangle L M Q is cut by perpendicular bisector L N. Angle N L Q is 32 degrees and angle L M N is 58 degrees.
Serga [27]

Answer:

Yes

Step-by-step explanation:

ΔMNL ≅ ΔQNL  by ASA or AAS

by ASA

Proof:

∠ LNM = ∠LNQ    =90

LN = LN   {Common}

∠MLN = ∠QLN     {LN bisects ∠ L}

By AAS

∠Q + ∠QLN + ∠LNQ = 180  {Angle sum property of triangle}

∠Q + 32 + 90 = 180

∠Q  + 122 = 180

∠Q = 180 -122 =

∠Q = 58

∠Q = ∠M

∠MNL =∠QNL = 90

LN = LN {common side}

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Step-by-step explanation:

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Step-by-step explanation:

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