Any of the tens i think (10=60, 20+50, etc.), but i am not too sure what is implied by regrouping. if i am right in thinking this only means "carrying" a digit after adding, then anything that adds up to 70 would work unless the sum of the digits in the ones place exceeded 9.
Given:
420 tropical fishes
angel fish = x
parrot fish = 6x
x + y = 420
y = 6x Choice D.
x + y = 420
y = 6x
x + 6x = 420
7x = 420
x = 420 / 7
x = 60 number of angelfish
y = 6x
y = 6(60)
y = 360 number of parrot fish
Answer:
7/12
Step-by-step explanation:
well first you have subtract 2/3 from 1/12 how you do that is that you have to change the denominator into twelve by multiplying 3 times 4 and 2 times for which you get 8/12 them subtract 8/12 from 1/12 which is 7/12
Answer: y=759
Step-by-step explanation:
y = (25 - 2) (35 - 2)
y = (23) (33)
y = 759
Simplify:
A(n) = -6 + (n - 1)(6) = -6 + (n)(6) + (-1)(6) = -6 + 6n - 6 = 6n - 12
Put n = 1, n = 4 and n = 10 to the expression:
A(1) = 6(1) - 12 = 6 - 12 = -6
A(4) = 6(4) - 12 = 24 - 12 = 12
A(10) = 6(10) - 12 = 60 - 12 = 48
<h3>Answer:</h3><h3>first term = -6, fourth term = 12 and tenth term = 48.</h3><h3>-6, 12, 48</h3>
