<span>x2 – 4x – 12 A) (x – 6)(x + 2)
x2 + 4x – 12 B) Prime
x2 – x – 12 C) (x – 4)(x + 3)
x2 – 7x – 12 D) (x – 2)(x + 6) i think this is the awnser:)</span>
Answer: 4 years
Step-by-step explanation:
A(0) has to be amount at start. Assume that's 5mg
Then A(t) = 5×(0.5)^(0.25t) = 5×2^(-t/4),
(also known as 5 exp(-λ t) with λ = ln(2)/4, incidentally).
We need to such that A(t) = 2.5mg, or 2^(-t/4) is 1/2, which happens when -t/4 is -1, or t is 4.
A translation of 4 units down means subtract 4 from the y-coordinate.
A translation of 5 units right means add 5 to the x-coordinate.
The new polygon will have vertices
A'(-1, 1)
B'(-1, -2)
C'(3, -2)
D'(3, 2)
Answer:
x=4
Step-by-step explanation:
<u>Step 1</u>:-
given the lengths of two sides of a right angle are represented by 2x and 3(x+1) and longest side is 17 units.
AB = 2x and BC = 3(x+1) and longest side AC= 17
by using Pythagoras theorem

<u>step 2:-</u>
The hypotenuse is longest side is AC = 17 units
(17)^2 = 4x^2 +9(X+1)^2
on simplification, we will use formula

289 = 4x^2 +9(x^2+2x+1)

finding factors 70 X 52 = 3640


Taking common , we get
13x(x-4)+70(x-4)=0
x-4=0 and 13x+70=0
x=4 and 
x=4 and 
we can not choose negative value so x value is 4
Final answer:- x = 4
<u>verification:-</u>
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289 = 4(4)^2+9(4+1)^2
289 = 64 +9(25)
289=289