Answer:
A(2, -3) and B(3, -2), o(0, 0) Let C(x, y)
Here c divide AB line in the ratio of 1:2
From the line intersection law, we get x=(m1×x2+m2×x1)/(m1+m2)
and y=(m1×y2+m2×y1)/(m1+m2)
where m1=1, m2=2, x1=2, x2=3, y1=-3, y2=-2;
so x=(3+4)/3
or, x=7/3;
y=(-2-6)/3
or, y=-8/3;
so, oc=√((0-7/3)²+(0-(-8/3))²)
oc=3.54
Answer:
C. 0 6 10
Step-by-Step-Explanation:
the number on the left of the indicated operation is the original set
the number '2' next to R shows that you need to multiply certain numbers by 2
the subscript on the R's shows which row the multiplication needs to be done on...
so in this case, leave the second row alone: 1 3 4
but multiply the first row by 2: 0 6 10
Answer:
Step-by-step explanation:
Factor the numerator and cancel common factors from numerator and denominator.
What is the solution set of x2 + y2 = 26 and x − y = 6? A. {(5, -1), (-5, 1)} B. {(1, 5), (5, 1)} C. {(-1, 5), (1, -5)} D. {(5,
Rus_ich [418]
He two equations given are
x^2 + y^2 = 26
And
x - y = 6
x = y +6
Putting the value of x from the second equation to the first equation, we get
x^2 + y^2 = 26
(y + 6) ^2 + y^2 = 26
y^2 + 12y + 36 + y^2 = 26
2y^2 + 12y + 36 - 26 = 0
2y^2 + 12y + 10 = 0
y^2 + 6y + 5 = 0
y^2 + y + 5y + 5 = 0
y(y + 1) + 5 ( y + 1) = 0
(y + 1)(y + 5) = 0
Then
y + 1 = 0
y = -1
so x - y = 6
x + 1 = 6
x = 5
Or
y + 5 = 0
y = - 5
Again x = 1
So the solutions would be (-1, 5), (1 , -5). The correct option is option "C".
Answer:
0
Step-by-step explanation:
The sorted data set is ...
1 2 3 3 5 7 8 9
The median is the average of the middle two numbers: (3+5)/2 = 4.
Replacing one of the 3s with a 1 makes the data set be ...
1 1 2 3 5 7 8 9
The average of the middle two numbers is (3+5)/2 = 4.
The median increases by 4 - 4 = 0.
