Which data set has an outlier? 25, 36, 44, 51, 62, 77 3, 3, 3, 7, 9, 9, 10, 14 8, 17, 18, 20, 20, 21, 23, 26, 31, 39 63, 65, 66,
umka21 [38]
It's hard to tell where one set ends and the next starts. I think it's
A. 25, 36, 44, 51, 62, 77
B. 3, 3, 3, 7, 9, 9, 10, 14
C. 8, 17, 18, 20, 20, 21, 23, 26, 31, 39
D. 63, 65, 66, 69, 71, 78, 80, 81, 82, 82
Let's go through them.
A. 25, 36, 44, 51, 62, 77
That looks OK, standard deviation around 20, mean around 50, points with 2 standard deviations of the mean.
B. 3, 3, 3, 7, 9, 9, 10, 14
Average around 7, sigma around 4, within 2 sigma, seems ok.
C. 8, 17, 18, 20, 20, 21, 23, 26, 31, 39
Average around 20, sigma around 8, that 39 is hanging out there past two sigma. Let's reserve judgement and compare to the next one.
D. 63, 65, 66, 69, 71, 78, 80, 81, 82, 82
Average around 74, sigma 8, seems very tight.
I guess we conclude C has the outlier 39. That one doesn't seem like much of an outlier to me; I was looking for a lone point hanging out at five or six sigma.
Answer:
Ooh man, this was back in geometry I think, I think the answer is 4 if my calculations are correct.
i think the bigger side is twice the size of the smaller side, so 2 times 8 is 16,
16 = 5x - 4
x = 4
Answer:
Measure the height of the cushion if you are covering a box cushion. Multiply the width of the cushion by two and the depth of the cushion by two, and add those numbers together to figure out how much fabric you will need to make the sides, front and back of the box cushion. Add 2 inches for seam allowances.
Step-by-step explanation:
I'm assuming this is 0.1666666...
Which in that case is 1/6.
(Just from memory)
To do 0.161616161616...
First, assign 0.161616... a variable, say it's x.
Now say 100x, what is it.
16.1616161616...
Now subtract x from 100x.
16.161616161616... - 0.16161616...
Or, 99x
99x = 16 in this case right now
Divide both sides by 99
x = 16/99
So it really depends what's repeating, it's either 1/6 or 16/99.
