Need answer to it solve it with the elimincation method with addition
2 answers:
You might be interested in
Answer:
The expected number of checks among 784 that should have a leading digit of "1" is 236.
Step-by-step explanation:
Let <em>X</em> = number of checks that has the leading digit as "1".
The probability of a check having a leading digit as "1" is, <em>p</em> = 0.301.
The number of checks issued by a suspected company is, <em>n</em> = 784.
A check is having a leading digit "1" is independent of other checks.
A randomly selected check either has the leading digit 1 or not.
The success of the experiment is defined as, a check having the digit "1" as the leading digit.
The random variable <em>X</em> follows a Binomial distribution with parameters <em>n</em> = 784 and <em>p</em> = 0.301.
The expected value of a random variable is the average number of times the random variable occurs.
The formula to compute the expected value of a Binomial distribution is:
Compute the expected value of <em>X</em> as follows:
Thus, the expected number of checks among 784 that should have a leading digit of "1" is 236.
Answer
• Line m: x = 3
,• Line n: y = –4
Explanation
If a line has no y-intercept, it means it must be parallel to the y - axis. Thus, it is a vertical line that will only cross the x-axis once (in this case).
As we are given that the x-intercept is (3,0), then the equation of line m is:
Following the same logic, if a line has no x-intercept, it will be parallel to the x-axis and it will be a vertical line.
As we are given that the y-intercept is (0,-4), then the equation of line n is: