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3 years ago

Given the equations of the lines 2x – y = 4 and 3x + 2y = -1. Do these lines intersect? If

Mathematics

1 answer:

sweet [91]3 years ago

6 0

Answer:

here you go i hope it helped

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Find the surface area of the square pyramid 8mm 6mm

bija089 [108]

Answer:

136 mm²

Step-by-step explanation:

$A=a^{2} +2a\sqrt{\frac{a^{2} }{4} } +h^{2}$

$A=6^{2} +2(6)\sqrt{\frac{6^{2} }{4} } +8^{2}$

$A=36 +12\sqrt{\frac{36 }{4} } +64$

$A=36 +12\sqrt{9 } +64$

$A=36 +12(3)+64$

$A=36 +36+64$

A = 136

5 0

3 years ago

Define contrapositive p --> q=?

siniylev [52]

Answer:

~q→~p

Step-by-step explanation:

The contrapositive of a statement is formed by negating the hypothesis and conclusion of a statement and switching them (the hypothesis becomes the conclusion and vice versa).

With this definition we can conclude that the contrapositive of p→q would be ~q→~p

3 0

3 years ago

Describe the effect an increase in i, the interest rate applied to the present value, has on the monthly payment P in the formul

VARVARA [1.3K]

Answer:

B. An increase in i, the interest rate, will create an increase in P, the monthly payment.

Step-by-step explanation:

We have the formula for the monthly payment as,

$P=\frac{i \times PV}{1-(1+i)^{-n} }$ ,

where P = monthly payment, i = rate of interest, PV = present value and n = time period.

Now, as i increase we get that (1+i) increases and so $(1+i)^{n}$ increases.

This gives us that, $\frac{1}{(1+i)^{n} }$ decreases and so $1-\frac{1}{(1+i)^{n}}$ decreases

Therefore, $\frac{1}{1-(1+i)^{-n} }$ increases.

So, we get that as i increases , the value of P will increase.

Hence, option B is correct.

4 0

3 years ago

Read 2 more answers

Draw to show 55 three different ways

MAXImum [283]

Needs more information.

6 0

3 years ago

Read 2 more answers

The table shows the ratio of caramel corn to cheddar cornvin a bag. What is the constant propotionality?

zvonat [6]

Since we know is a proportionality, namely a multiplier on "x", we can simply use any of those points, say hmmm let's use 10, 15,

$\bf \qquad \qquad \textit{direct proportional variation}\\\\
\textit{\underline{y} varies directly with \underline{x}}\qquad \qquad y=kx\impliedby 
\begin{array}{llll}
k=constant\ of\\
\qquad variation
\end{array}\\\\
-------------------------------\\\\
\textit{we know that }
\begin{cases}
x=10\\
y=15
\end{cases}\implies 15=k10\implies \cfrac{15}{10}=k\implies \cfrac{3}{2}=k$

8 0

3 years ago