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Dafna1 [17]
3 years ago
7

Which equation represent this relation

Mathematics
1 answer:
ddd [48]3 years ago
5 0

Answer:

hello,

answer A c=n+2

Step-by-step explanation:

if n=0 then c=2

if n=2 then c=4

slope=m=(4-2)/(2-0) =2/2=1

c-2=1*(n-0)

c=n+2

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Which number is rational? ​
Romashka [77]

Answer:

5.3333333...

Step-by-step explanation:

5.\overline3 = \dfrac{53-5}{9} = \dfrac{48}9

4 0
2 years ago
Please need help fast. Look at the picture.<br><br> Please explain.
Zigmanuir [339]
The answer is 17

This is because 1 + 2 must equal 180 as they are in a straight line.
So 4x + 2 + 110 = 180
Take away 110 from both sides
4x + 2 = 70
Take away 2 from both sides to get 4x = 68. Finally, divide both sides by 4 to get x = 17
7 0
3 years ago
What's the answer? ​
Travka [436]

Answer:

80 degrees

Step-by-step explanation:

ALL TRIANGLES MUST EQUAL 180 DEGREES!

180-70-30 = 80

Say it with me.

<em>ALL TRIANGLES MUST EQUAL 180 DEGREES!</em>

<em>ALL TRIANGLES MUST EQUAL 180 DEGREES!</em>

<em>ALL TRIANGLES MUST EQUAL 180 DEGREES!</em>

Also, triangle CED reflects over the invisible y-axis. Angle C is shared = 70. Angle E is Angle A, and Angle B is Angle D (which is 80 degrees).

3 0
3 years ago
The number of swings in use on average is.
Veseljchak [2.6K]

Answer:

?

Step-by-step explanation:

7 0
3 years ago
Math help Please!!!!
GalinKa [24]

Part A. What is the slope of a line that is perpendicular to a line whose equation is −2y=3x+7?

Rewrite the equation  −2y=3x+7 in the form y=-\dfrac{3}{2}x-\dfrac{7}{2}. Here the slope of the given line is  m_1=-\dfrac{3}{2}. If m_2 is the slope of perpendicular line, then

m_1\cdot m_2=-1,\\ \\m_2=-\dfrac{1}{m_1}=\dfrac{2}{3}.

Answer 1: \dfrac{2}{3}

Part B. The slope of the line y=−2x+3 is -2. Since -\dfrac{3}{2}\neq -2\quad \text{and}\quad \dfrac{2}{3}\neq -2, then lines from part A are not parallel to line a.

Since -2\cdot \left(-\dfrac{3}{2}\right)=3\neq -1\quad \text{and}\quad -2\cdot \dfrac{2}{3}=-\dfrac{4}{3}\neq -1, both lines are not perpendicular to line a.

Answer 2: Neither parallel nor perpendicular to line a

Part C. The line parallel to the line 2x+5y=10 has the equation 2x+5y=b. This line passes through the point (5,-4), then

2·5+5·(-4)=b,

10-20=b,

b=-10.

Answer 3: 2x+5y=-10.

Part D. The slope of the line y=\dfrac{x}{4}+5 is \dfrac{1}{4}. Then the slope of perpendicular line is -4 and the equation of the perpendicular line is y=-4x+b. This line passes through the point (2,7), then

7=-4·2+b,

b=7+8,

b=15.

Answer 4: y=-4x+15.

Part E. Consider vectors \vec{p}_1=(-c-0,0-(-d))=(-c,d)\quad \text{and}\quad \vec{p}_2=(0-b,a-0)=(-b,a). These vectors are collinear, then

\dfrac{-c}{-b}=\dfrac{d}{a},\quad \text{or}\quad -\dfrac{a}{b}=-\dfrac{d}{c}.

Answer 5: -\dfrac{a}{b}=-\dfrac{d}{c}.

5 0
4 years ago
Read 2 more answers
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