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kherson [118]
3 years ago
8

Can someone please help me ?

Mathematics
1 answer:
tiny-mole [99]3 years ago
3 0

Answer:

the radical has an index of 3;to solve for x find the cubic root of 729, x= 9

Step-by-step explanation:

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Select the equivalent expression.<br> 3-5 =?<br> Choose 1 answer:
makkiz [27]
3-5 is equal to -2 (hope this helps you) :)
6 0
3 years ago
If the rate of the boat in still water is 27 mph, and the rate of the current of a river is x mph, what is the rate of the boat
BigorU [14]

Answer:

a)27-x

b)27+x

Step-by-step explanation:

when a boat travels in the same direction as the current is downstream-->speeds the boat. If the rate of the boat in still water is 27 mph and the rate of the current of a river is x mph, the rate of the boat when the boat is going downstream is 27+x

when a boat travels against the current is upstream-->slow down. If the rate of the boat in still water is 27 mph and the rate of the current of a river is x mph, the rate of the boat when the boat is going upstream is 27-x

6 0
3 years ago
Jamie puts $500 into a savings account that has an interest rate of 1% how much will be in her account after 6 years?
IgorLugansk [536]

Step-by-step explanation:

interest:

500 \times \frac{1}{100}  \times 6 = 30

Total=500+30=530

4 0
3 years ago
Graph the function and its parent function on the calculator . Then describe the transformation.
Nuetrik [128]
“Vertical translation up” because the parents fuction which is the f(x) is equal to x^2
4 0
3 years ago
A college is planning to construct a rectangular parking lot on land bordered on one side by a highway. The plan is to use 680 f
ElenaW [278]

Answer:

The maximum length is 170 feet and maximum width is 340 feet.

Step-by-step explanation:

Let the length of the parking = x feet and width = y feet.

Since, the fencing is to be applied on three sides of the lot.

So,we get, 2x+y=680

i.e. y=680-2x

Since, the area of the rectangular lot = Length × Width

So, area of the lot = x \times y

i.e. area of the lot = x \times (680-2x)

i.e. area of the lot = 680x-2x^2

Now, we know the maximum value of 'x' in ax^2+bx+c is \frac{-b}{2a}.

So, the maximum length of the lot is x= \frac{-680}{2\times -2} = \frac{680}{4} = 170 feet.

Then, y=680-2x i,plies y=680-2\times 170 implies y=680-340 i.e. y= 340 feet.

So, the maximum length is 170 feet and maximum width is 340 feet.

6 0
3 years ago
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