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Tom [10]
3 years ago
13

Simplify: 1 1/2*1 1/3*1 1/4*1 1/5*1 1/6*...*1 1/n

Mathematics
2 answers:
Orlov [11]3 years ago
7 0

Answer:

i dont know sorry!

Step-by-step explanation:

dsp733 years ago
6 0

Step-by-step explanation:

(1 + 1/2)(1 + 1/3)(1+ 1/4)...(1 + 1/n)

= (3/2)(4/3)(5/4)...[(n+1)/n]

= 0.5(n+1).

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Which equation can be used to solve a – 5 = 30?
kari74 [83]

Answer:

last one

a = 30 + 5

a - 5 = 30

Step-by-step explanation:

here is your answer

4 0
2 years ago
43.
aleksklad [387]

Answer:

4.12 kg

Step-by-step explanation:

Regular cakes:

1 dozen normal sponge cakes: 264 g plain flour

Vegetarian cakes:

1 dozen cakes: 264 g plain flour

4 eggs are replaced by 4 * 30 g of flour = 120 g flour

total flour for 1 dozen vegetarian cakes = 264 g + 120 g = 384 g

Proportion for regular cakes:

12 cakes to 264 g flour = 100 cakes to x grams flour

12/264 = 100/x

12x = 26400

x = 2200

2200 g flour for 100 regular cakes

Proportion for vegetarian cakes:

12 cakes to 384 g flour = 60 cakes to y grams flour

12/384 = 60/y

12y = 384 * 60

12y = 23040

y = 1920

1920 g flour for 60 vegetarian cakes

Total flour needed:

2200 g + 1920 g = 4120 g

4120 g * 1 kg/(1000 g) = 4.12 kg

Answer: 4.12 kg

4 0
3 years ago
Whats the length of the short side?
anzhelika [568]

Call the short side x.   We have

tan 72° = opposite/adjacent =  (12.8 cm) / x

x = 12.8 / tan 72° = 12.8/(3.01) = 4.158...

Answer: 4.2 cm


3 0
3 years ago
The general solution of 2 y ln(x)y' = (y^2 + 4)/x is
Sav [38]

Replace y' with \dfrac{\mathrm dy}{\mathrm dx} to see that this ODE is separable:

2y\ln x\dfrac{\mathrm dy}{\mathrm dx}=\dfrac{y^2+4}x\implies\dfrac{2y}{y^2+4}\,\mathrm dy=\dfrac{\mathrm dx}{x\ln x}

Integrate both sides; on the left, set u=y^2+4 so that \mathrm du=2y\,\mathrm dy; on the right, set v=\ln x so that \mathrm dv=\dfrac{\mathrm dx}x. Then

\displaystyle\int\frac{2y}{y^2+4}\,\mathrm dy=\int\dfrac{\mathrm dx}{x\ln x}\iff\int\frac{\mathrm du}u=\int\dfrac{\mathrm dv}v

\implies\ln|u|=\ln|v|+C

\implies\ln(y^2+4)=\ln|\ln x|+C

\implies y^2+4=e^{\ln|\ln x|+C}

\implies y^2=C|\ln x|-4

\implies y=\pm\sqrt{C|\ln x|-4}

4 0
3 years ago
Iven that 1 9x x2 + 9 dx 0 = 30 10 − 81, what is 0 9u u2 + 9 du 1 ?
katrin [286]
Check the attached file for the solution.

5 0
4 years ago
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