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Svetllana [295]
3 years ago
14

4. What's the least common multiple of each group of numbers?

Mathematics
1 answer:
mina [271]3 years ago
8 0

Answer:

D. 2,5, and 6

Step-by-step explanation:

Because if u mutiply 2*5 = 10 and 2*6 is 12 as 5*6 is 30 and 2*9 is 18 .

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State the domain and range of the relation. Determine whether the relation represents a function.
dangina [55]

Answer:

Domain {-2,0,2}

Range {-2,0,2}

Relation is a Function

Step-by-step explanation:

We are given a relation:

{ (-2,-2) , (0,0) , (2,2) }

Domain can be defined as the all possible values of x for a relation. It is considered as a set of all first values of the ordered pairs of a given relation.

Domain of the given relation is {-2,0,2}

Range can be defined as all possible value of y which corresponds to the values of x in the domain. It is considered as a set of all second values of the ordered pairs of a given relation.

Range of the given relation is {-2,0,2}

A relation is a function if only there is one value of y for each value of x. If in the set of ordered pair of the relation, the value of x gets repeated, then the relation is not a function.

As no values of x are getting repeated, the relation is a function.

4 0
3 years ago
What is the equivalent measure of 78 centiliters in milliliters?
Maurinko [17]
170 milliliters is the answer
3 0
3 years ago
Read 2 more answers
F⃗ (x,y)=−yi⃗ +xj⃗ f→(x,y)=−yi→+xj→ and cc is the line segment from point p=(5,0)p=(5,0) to q=(0,2)q=(0,2). (a) find a vector pa
DerKrebs [107]

a. Parameterize C by

\vec r(t)=(1-t)(5\,\vec\imath)+t(2\,\vec\jmath)=(5-5t)\,\vec\imath+2t\,\vec\jmath

with 0\le t\le1.

b/c. The line integral of \vec F(x,y)=-y\,\vec\imath+x\,\vec\jmath over C is

\displaystyle\int_C\vec F(x,y)\cdot\mathrm d\vec r=\int_0^1\vec F(x(t),y(t))\cdot\frac{\mathrm d\vec r(t)}{\mathrm dt}\,\mathrm dt

=\displaystyle\int_0^1(-2t\,\vec\imath+(5-5t)\,\vec\jmath)\cdot(-5\,\vec\imath+2\,\vec\jmath)\,\mathrm dt

=\displaystyle\int_0^1(10t+(10-10t))\,\mathrm dt

=\displaystyle10\int_0^1\mathrm dt=\boxed{10}

d. Notice that we can write the line integral as

\displaystyle\int_C\vecF\cdot\mathrm d\vec r=\int_C(-y\,\mathrm dx+x\,\mathrm dy)

By Green's theorem, the line integral is equivalent to

\displaystyle\iint_D\left(\frac{\partial x}{\partial x}-\frac{\partial(-y)}{\partial y}\right)\,\mathrm dx\,\mathrm dy=2\iint_D\mathrm dx\,\mathrm dy

where D is the triangle bounded by C, and this integral is simply twice the area of D. D is a right triangle with legs 2 and 5, so its area is 5 and the integral's value is 10.

4 0
3 years ago
Find the radius or diameter of each circle with the given dimensions.<br><br> d=30 m
Alex_Xolod [135]

Answer:

r=94.2

Step-by-step explanation:

C=pi`d

C=3.14 multiplied by 30

C equals about 94.2

6 0
3 years ago
If you doubled the radius of a sphere, how would the volume change? A. The volume would double. B. The volume would triple. C. T
Ronch [10]
The volume of a sphere, V = (4/3)(PI)(R^3) Let k = (4/3)(PI) Therefore, V = k (R^3) Let R’ = new radius = 2R V’ =k (R’^3) = k (2R)^3 = 8 k R^3 = 8 V The volume would be eight time the original volume.
7 0
3 years ago
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