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frutty [35]
3 years ago
14

What’s 4d plus 12e in distributive property

Mathematics
1 answer:
jeka57 [31]3 years ago
6 0
I am not 100% certain but i believe it goes as follows:

4 ( 1 + d ) + ( 3 + e)
4d + 12e
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Use a sales tax rate of 7%.Estimate the total cost for each item.a bicycle that costs $129
svet-max [94.6K]

Answer:

$138.03

Step-by-step explanation:

1.07*129 =138.03 represents an increase of 7%

6 0
3 years ago
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A freight train travels at 30 mph. If the freight train is 300 miles ahead of an express train traveling at 55 mph, how long wil
melisa1 [442]
Distance<-------------300--------------><-------------------x----------------->
          ⊕---------------------------------⊕--------------------------------------⊕                      Express                                  Freight                            Overtaking point
   Speed 55                              speed 30

Let x be the distance travelled by Freight until the point of overtaking
Time = Distance/Speed, then:

Time (freight) = Distance (fright)/Speed (freight) And
Time (Express) = Distance (Express)/Speed (Express).
Now plug in the relative number:

Time (freight) = x/30  and Time (express) = (x+300)/55. But note that both times are equal, then:
x/30 = (x+300)/55 OR (x÷30 = (x+300)÷55) [Answer C]
Now let's find the distance x. Cross multiplication;

55x= 30(300+x) →55x = 9,000 + 30x
55x - 30x = 9,000 → 25x = 9,000 and x = 9,000/25 = 360 miles
Time needed for Freight to travel 360 m = 360/30= 12 Hours
Time needed for Express to travel (300+360) m = 660/55= 12 Hours
As you see, it's the same time of 12 hours
Don't forget that Distance = Speed x time or time = Distance/Speed, etc.

4 0
3 years ago
Read 2 more answers
determine The length of the circular arc of a circle with a radius of 49 cm subtended by a central angle of 135°
Katena32 [7]

Given:

Length of the circular arc with circle radius=49cm

θ=135°

Now,

Length of arc = θ/360°×2πr

49=2× 22/7×r×135°/360°

49×20×7/3×22×2

51.96cm

6 0
1 year ago
Anyone help me please,find the area of each figure.​
Morgarella [4.7K]

Hey there! :)

Answer:

170 cm².

Step-by-step explanation:

This is an example of a composite figure, so find the areas of each shape separately:

Begin by finding the area of the smaller square. A = s²

A = 7² = 49 cm².

Find the area of the larger square:

A = 11² = 121 cm².

Add up the two areas:

49 + 121 = 170 cm².

5 0
3 years ago
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Suppose you can somehow choose two people at random who took the SAT in 2014. A reminder that scores were Normally distributed w
Sindrei [870]

Answer:

22.29% probability that both of them scored above a 1520

Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

\mu = 1497, \sigma = 322

The first step to solve the question is find the probability that a student has of scoring above 1520, which is 1 subtracted by the pvalue of Z when X = 1520.

So

Z = \frac{X - \mu}{\sigma}

Z = \frac{1520 - 1497}{322}

Z = 0.07

Z = 0.07 has a pvalue of 0.5279

1 - 0.5279 = 0.4721

Each students has a 0.4721 probability of scoring above 1520.

What is the probability that both of them scored above a 1520?

Each students has a 0.4721 probability of scoring above 1520. So

P = 0.4721*0.4721 = 0.2229

22.29% probability that both of them scored above a 1520

8 0
2 years ago
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