All categories

3 years ago

Please, I really need help with this! What is the volume of this cone?

Mathematics

1 answer:

vova2212 [387]3 years ago

7 0

By definition, the volume of a cone is given by:
$V = \frac{1}{3} * (\pi) * (r ^ 2) * (h)
$
Where,
r: radius of the circular base
h: height of the cone
Substituting values we have:
$V = \frac{1}{3} * (3.14) * (11 ^ 2) * (16)

V = 2026.346667$
Rounding to the nearest hundredth we have:
$V = 2026.35 m ^ 3
$
Answer:
the volume of this cone is:
$V = 2026.35 m ^ 3$

You might be interested in

Which number should she subtract from both sides of the equation?

bezimeni [28]

Where’s the problem where it explains what’s she is subtracting?

7 0

3 years ago

Find answers 1-8 show work please.

crimeas [40]

Answer:

hope this helps you out good luck with your math

5 0

3 years ago

The sum of two numbers is 59 and the difference is 5 what are the numbers

svlad2 [7]

Answer:

32 and 27

Step-by-step explanation:

59 - 5 = 54

54 ÷ 2 = 27( smallest no. )

27 + 5 = 32( largest no. )

3 0

3 years ago

Read 2 more answers

Newton's law of cooling is:

Mnenie [13.5K]

Answer:

$t = \frac{ln(\frac{21}{59})}{-0.15}=6.887 hr$

So it would takes approximately 6.9 hours to reach 32 F.

Step-by-step explanation:

For this case we have the following differential equationÑ

$\frac{du}{dt}= -k (u-T)$

We can reorder the expression like this:

$\frac{du}{u-T} = -k dt$

We can use the substitution $w = u-T$ and $dw =du$ so then we have:

$\frac{dw}{w} =-k dt$

IF we integrate both sides we got:

$ln |w| = -kt +C$

If we apply exponential in both sides we got:

$w = e^{-kt} *e^c$

And if we replace w = u-T we got:

$u(t)= T + C_1 e^{-kt}$

We can also express the solution in the following terms:

$u(t) = (T_i -T_{amb}) e^{kt} +T_{amb}$

For this case we know that $k =-0.15 hr$ since w ehave a cooloing, $T_{i}= 70 F, T_{amb}=11F$ , we have this model:

$u(t) = (70-11) e^{-0.15t} +11$

And if we want that the temperature would be 32F we can solve for t like this:

$32 = 59 e^{-0.15 t} +11$

$21=59 e^{-0.15 t}$

$\frac{21}{59} = e^{-0.15 t}$

If we apply natural logs on both sides we got:

$ln (\frac{21}{59}) =-0.15 t$

$t = \frac{ln(\frac{21}{59})}{-0.15}=6.887 hr$

So it would takes approximately 6.9 hours to reach 32 F.

7 0

4 years ago

How do i calculate the percentage difference between two numbers????

lawyer [7]

When finding the percent difference between two numbers, there are two ways you can do this.

1. The first way is how to calculate the percentage INCREASE of two numbers:

-The formula is Increase / Original Number × 100 = % increase

Step 1: Find out the difference between the two numbers you're comparing. New number - Original number = Increase.

Step 2: Divide the increase by the original number and then multiply your answer by 100. (If your answer is a negative number, then it is a percent decrease, not a percent increase.)

2. The second way is how to calculate the percentage DECREASE of two numbers:

Step 1: Find out the difference between the two numbers you're comparing. Original number - New number = Decrease.

Step 2: Divide the decrease by the original number and then multiply your answer by 100. Decrease ÷ Original Number × 100 = % Decrease. (If your answer is a negative number, then is is a percent increase, not a percent decrease.)

8 0

3 years ago