Question

C=5/9(F-32) for F Solve the Equation for the given Variable

Answer 1

C = 5/9(F - 32)...multiply both sides by 9/5, eliminating the 5/9 on the right
9/5C = F - 32...add 32 to both sides
9/5C + 32 = F <===

Answer 2

C=$\frac{5}{9}$ F-32

9C=5(F-32)

$\frac{9C}{5}$=F-32

$\frac{9C}{5}$+32=F

F=$\frac{9C}{5}$+32