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Sedbober [7]
3 years ago
13

C=5/9(F-32) for F Solve the Equation for the given Variable

Mathematics
2 answers:
Jlenok [28]3 years ago
5 0
C = 5/9(F - 32)...multiply both sides by 9/5, eliminating the 5/9 on the right
9/5C = F - 32...add 32 to both sides
9/5C + 32 = F <===
snow_tiger [21]3 years ago
4 0
C=\frac{5}{9} F-32

9C=5(F-32)

\frac{9C}{5}=F-32

\frac{9C}{5}+32=F

F=\frac{9C}{5}+32
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Step-by-step explanation:

We are given the following in the question:

4.751, 4.373, 4.177, 4.676, 4.425, 4.228, 4.125, 4.251, 3.951, 4.192, 4.291, 4.414

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\text{Standard Deviation} = \sqrt{\displaystyle\frac{\sum (x_i -\bar{x})^2}{n-1}}  

where x_i are data points, \bar{x} is the mean and n is the number of observations.  

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\bar{x} \pm t_{critical}\displaystyle\frac{s}{\sqrt{n}}  

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4.321 \pm 2.718(\frac{0.226}{\sqrt{12}} ) = 4.321 \pm 0.1773 = (4.144 ,4.498)  

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Step-by-step explanation:

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