To solve this problem, we need to first find the dimensions of the side of the blue and purple squares.
We're given that the purple (smaller) square has a side length of x inches.
We are also given that the blue band has a width of 5 inches.
Since the blue band surrounds the purple square on both sides, the length of the blue square is x+2(5)=x+10 inches.
The net area of the band is therefore the difference of the area of the blue square and the purple square, namely take out the area of the purple square from the blue.
Therefore
Area of band

[recall



or 20(x+5) if you wish.
Answer:
1.75 inches or 1 3/4inches
Step-by-step explanation:
A map has a scale of ½½inch=20mles. Quinn wants to travel an actual distance of 70miles. What will the length on the map be?
70/20
=7/2
=1/2×7/2
=7/4
=1 3/4 inches
in decimal its 1.75 inches
<em>29 ml</em>
- Step-by-step explanation:
<em>Vcube = 1cm×1cm×1cm = 1 cm³</em>
<em>1 cm³ = 1 ml</em>
<em>If this cube is dropped into a 28ml of water the new reading will be 29 ml.</em>
The interest is simple
A=5,200×(1+0.04×5)
A=6,240
90
55+65=120
there are 3 numbers and when you divide them it makes 70.
70 x 3 = 210
210 - 120 = 90
55 + 65 + 90 = 210
210 / 3 = 70