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NNADVOKAT [17]
2 years ago
11

The following structure is composed of three right rectangular prisms: two that each measure 12 inches by 10 inches by 5 inches

and one right rectangular prism that measures 10 inches by 8 inches by 36 inches. What is the total volume of the structure? Show your work and/or explain your reasoning..
Mathematics
1 answer:
GalinKa [24]2 years ago
5 0

The volume of the stucture made from three rectangular prism is 4080 ft³

<h3>What is volume?</h3>

Volume is the amount of space occupied by a three dimensional shape or object.

The volume of the rectangular prism = length * width * height = 12 * 10 * 5 = 600 ft³

The volume of the other prism = length * width * height = 10 * 8 * 36 = 2880 ft³

Volume of the structure = 600 ft³ + 600 ft³ + 2880 ft³ = 4080 ft³

The volume of the stucture made from three rectangular prism is 4080 ft³

Find out more on volume at: brainly.com/question/12410983

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Answer:

C. 275.88‬ m squared

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Which statement is NOT true about the ratio of the leg lengths of increment ΔLRM and increment ΔJSK?
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7 0
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The equation giving a family of ellipsoids is u = (x^2)/(a^2) + (y^2)/(b^2) + (z^2)/(c^2) . Find the unit vector normal to each
Fynjy0 [20]

Answer:

\hat{n}\ =\ \ \dfrac{\dfrac{x}{a^2}\hat{i}+\ \dfrac{y}{b^2}\hat{j}+\ \dfrac{z}{c^2}\hat{k}}{\sqrt{(\dfrac{x}{a^2})^2+(\dfrac{y}{b^2})^2+(\dfrac{z}{c^2})^2}}

Step-by-step explanation:

Given equation of ellipsoids,

u\ =\ \dfrac{x^2}{a^2}+\dfrac{y^2}{b^2}+\dfrac{z^2}{c^2}

The vector normal to the given equation of ellipsoid will be given by

\vec{n}\ =\textrm{gradient of u}

            =\bigtriangledown u

           

=\ (\dfrac{\partial{}}{\partial{x}}\hat{i}+ \dfrac{\partial{}}{\partial{y}}\hat{j}+ \dfrac{\partial{}}{\partial{z}}\hat{k})(\dfrac{x^2}{a^2}+\dfrac{y^2}{b^2}+\dfrac{z^2}{c^2})

           

=\ \dfrac{\partial{(\dfrac{x^2}{a^2})}}{\partial{x}}\hat{i}+\dfrac{\partial{(\dfrac{y^2}{b^2})}}{\partial{y}}\hat{j}+\dfrac{\partial{(\dfrac{z^2}{c^2})}}{\partial{z}}\hat{k}

           

=\ \dfrac{2x}{a^2}\hat{i}+\ \dfrac{2y}{b^2}\hat{j}+\ \dfrac{2z}{c^2}\hat{k}

Hence, the unit normal vector can be given by,

\hat{n}\ =\ \dfrac{\vec{n}}{\left|\vec{n}\right|}

             =\ \dfrac{\dfrac{2x}{a^2}\hat{i}+\ \dfrac{2y}{b^2}\hat{j}+\ \dfrac{2z}{c^2}\hat{k}}{\sqrt{(\dfrac{2x}{a^2})^2+(\dfrac{2y}{b^2})^2+(\dfrac{2z}{c^2})^2}}

             

=\ \dfrac{\dfrac{x}{a^2}\hat{i}+\ \dfrac{y}{b^2}\hat{j}+\ \dfrac{z}{c^2}\hat{k}}{\sqrt{(\dfrac{x}{a^2})^2+(\dfrac{y}{b^2})^2+(\dfrac{z}{c^2})^2}}

Hence, the unit vector normal to each point of the given ellipsoid surface is

\hat{n}\ =\ \ \dfrac{\dfrac{x}{a^2}\hat{i}+\ \dfrac{y}{b^2}\hat{j}+\ \dfrac{z}{c^2}\hat{k}}{\sqrt{(\dfrac{x}{a^2})^2+(\dfrac{y}{b^2})^2+(\dfrac{z}{c^2})^2}}

3 0
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PLSSS HELP IF YOU TURLY KNOW THISS
solniwko [45]

Answer:

super simple its blueprints!

Step-by-step explanation:

7 0
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prisoha [69]
The answer is 3.

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