$5+20\cdot2^{2-3x}=10\cdot2^{-2x}+5\qquad\text{subtract 5 from both sides}\\\\20\cdot2^{2-3x}=10\cdot2^{-2x}\qquad\text{divide both sides by 10}\\\\2\cdot2^{2-3x}=2^{-2x}\qquad\text{use}\ a^n\cdot a^m=a^{n+m}\\\\2^{1+2-3x}=2^{-2x}\\\\2^{3-3x}=2^{-2x}\iff3-3x=-2x\qquad\text{subteact 3 from both sides}\\\\-3x=-2x-3\qquad\tex\qquad\text{add}\ 2x\ \text{to both sides}\\\\-x=-3\qquad\text{change the signs}\\\\x=3$

8 0

3 years ago

How do I solve 2(x+4x)-4=4(x-3)+2(x+10)

mixas84 [53]

2(x+4x)-4=4(x-3)+2(x+10)
2x+8x-4=4x-9+2x+20
10x-4=6x+11
10x=6x+15
4x=15
x=3.75

4 0

3 years ago

The graph represents function 1, and the equation represents function 2:

Elza [17]

The answer is C) 7.

In function 1, there is no rate of change.
In function 2, there is a rate of change of 7.
This leaves 7 as the only possible answer.

4 0

3 years ago

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Which tempature is the warmest

Mademuasel [1]

Answer:

D.) 21 degrees fahrenheit.

Step-by-step explanation:

From warmest to coldest:

d. 21 degrees

a. 16 degrees

b. -16 degrees

c. -21 degrees

Hope this helps you : )

4 0

3 years ago

Read 2 more answers